Compound interest on 8000 for 3 years at the rate of 9 p.a is

1. Find the amount of $ 12000 after 2 years, compounded annually; the rate of interest being 5 % p.a. during the first year and 6 % p.a. during the second year. Also, find the compound interest.

Solution:

Here, P = $12000, p = 5 % p.a. and q = 6 % p.a.

Using the formula A = {P × (1 + P/100) × (1 + q/100)}

amount after 2 years = $ {12000 × (1 + 5/100) × (1 + 6/100)}

= $ (12000 × 21/20 × 53/50)

=$ 13356

Thus, amount after 2 years = $ 13356

And, compound interest = $ (13356 – 12000)

Therefore, compound interest = $ 1356.

Case 3:

When interest is compounded annually but time is a fraction

For example suppose time is 2³/₅ years then,

Amount = P × (1 + R/100)² × [1 + (3/5 × R)/100]

1. Find the compound interest on $ 31250 at 8 % per annum for 2 years. Solution Amount after 2³/₄ years

Solution:

Amount after 2³/₄ years

= $ [31250 × (1 + 8/100)² × (1 + (3/4 × 8)/100)]

= ${31250 × (27/25)² × (53/50)}

= $ (31250 × 27/25 × 27/25 × 53/50)

= $ 38637.

Therefore, Amount = $ 38637,

Hence, compound interest = $ (38637 - 31250) = $ 7387.

Compound Interest by Using Formula, when it is calculated half-yearly

Interest Compounded Half-Yearly

Let principal = $ P, rate = R% per annum, time = a years.

Suppose that the interest is compounded half- yearly.

Then, rate = (R/2) % per half-year, time = (2n) half-years, and

amount = P × (1 + R/(2 × 100))²ⁿ

Compound interest = (amount) - (principal).

1. Find the compound interest on $ 15625 for 1¹/₂ years at 8 % per annum when compounded half-yearly.

Solution:

Here, principal = $ 15625, rate = 8 % per annum = 4% per half-year,

time = 1¹/₂ years = 3 half-years.

Amount = $ [15625 × (1 + 4/100)³]

=$ (15625 × 26/25 × 26/25 × 26/25)= $ 17576.

Compound interest = $ (17576 - 15625) = $ 1951.

2. Find the compound interest on $ 160000 for 2 years at 10% per annum when compounded semi-annually.

Solution:

Here, principal = $ 160000, rate = 10 % per annum = 5% per half-year, time = 2 years = 4 half-years.

Amount = $ {160000 × (1 + 5/100)⁴}

=$ (160000 × 21/20 × 21/20 × 21/20 × 21/20)

compound interest = $ (194481- 160000) = $ 34481.

Compound Interest by Using Formula, when it is calculated Quarterly

Interest Compounded Quarterly

Let principal = $ P. rate = R % per annum, time = n years.

Suppose that the interest is compounded quarterly.

Then, rate = (R/4) % Per quarter, time = (4n) quarters, and

amount = P × (1 + R/(4 × 100))⁴ⁿ

Compound interest = (amount) - (principal).

1. Find the compound interest on $ 125000, if Mike took loan from a bank for 9 months at 8 % per annum, compounded quarterly.

Solution:

Here, principal = $ 125000,

rate = 8 % per annum = (8/4) % per quarter = 2 % per quarter,

time = 9 months = 3 quarters.

Therefore, amount = $ {125000 × ( 1 + 2/100)³}

=$ (125000 × 51/50 × 51/50 × 51/50)= $ 132651

Therefore, compound interest $ (132651 - 125000) = $ 7651.

● Compound Interest

Compound Interest

Compound Interest with Growing Principal

Compound Interest with Periodic Deductions

Compound Interest by Using Formula

Compound Interest when Interest is Compounded Yearly

Compound Interest when Interest is Compounded Half-Yearly

Compound Interest when Interest is Compounded Quarterly

Problems on Compound Interest

Variable Rate of Compound Interest

Difference of Compound Interest and Simple Interest

Practice Test on Compound Interest

Uniform Rate of Growth

Uniform Rate of Depreciation

Uniform Rate of Growth and Depreciation

● Compound Interest - Worksheet

Worksheet on Compound Interest

Worksheet on Compound Interest when Interest is Compounded Half-Yearly

Worksheet on Compound Interest with Growing Principal

Worksheet on Compound Interest with Periodic Deductions

Worksheet on Variable Rate of Compound Interest

Worksheet on Difference of Compound Interest and Simple Interest

Worksheet on Uniform Rate of Growth

Worksheet on Uniform Rate of Depreciation

Worksheet on Uniform Rate of Growth and Depreciation

8th Grade Math Practice

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Rs.8000 for 3years at 10% per annum compounded annually.
Here P = Rs.8000, t = 3years, r = 10%
Now, Amount
= `"P"(1 + "r"/100)^"t"`

= `8000(1 + 10/100)^3`

= `8000(11/10)^3`

= `8000 xx (1331)/(1000)`
= 10648
Hence, Amount = Rs.10648
Also, C.I.
= A - P
= Rs.10648 - Rs.8000
= Rs.2648.

What will be the compound interest on 8000 for 3 years at 5% pa?

So compound interest is 9261.

What would be the compound interest of Rs 8000 at 10% interest rate after 3 years?

Find the amount of Rs 8000 for 3 years, compounded annually at 10% per annum. Also, find the compound interest. UPLOAD PHOTO AND GET THE ANSWER NOW! Answer : Rs 26 48.

What would be the compound interest accrued on ₹ 8000 at the rate of 15% pa in three years?

And compound interest = Rs. (10648−8000)=2648.

What is the formula for compound interest for 3 years?

Ans: Compound interest is the interest on a loan or deposit that accrues on both the initial principal and the accumulated interest from previous periods. Q. How do we calculate compound interest? Ans: We can calculate CI by using the formula for compound interest is A = P(1 + r/n)^nt.