Get day of month php

Today's date is 27-01-2014 so I got day name using following function:

$t=date['d-m-Y'];
$day = strtolower[date["D",strtotime[$t]]];

So now the day name is mon.

How to find that this Monday is the forth Monday of current month? In other words, I am trying to find the 1st, 2nd, 3rd, 4th of a particular day [eg. Monday] of a month?

asked Jan 27, 2014 at 9:58

DS9DS9

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7

Credit for the Math part goes to Jon [above]

In combination with your code, full solution can be implemented as follows

$t=date['d-m-Y'];
$dayName = strtolower[date["D",strtotime[$t]]];
$dayNum = strtolower[date["d",strtotime[$t]]];
echo floor[[$dayNum - 1] / 7] + 1

or else as a function with optional date

PHP Fiddle here

This just return the number you are requesting.

function dayNumber[$date='']{
    if[$date=='']{
        $t=date['d-m-Y'];
    } else {
        $t=date['d-m-Y',strtotime[$date]];
    }

    $dayName = strtolower[date["D",strtotime[$t]]];
    $dayNum = strtolower[date["d",strtotime[$t]]];
    $return = floor[[$dayNum - 1] / 7] + 1;
    return $return;
}


echo dayNumber['2014-01-27'];

answered Jan 27, 2014 at 10:36

Oliver M GrechOliver M Grech

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2

$date = mktime[0, 0, 0, 1, 27, 2014];
$dayNumber = date["d", $date];
$dayOfWeek = date["l", $date];
$dayPosition = [floor[[$dayNumber - 1] / 7] + 1];

switch [$dayPosition] {
    case 1:
        $suffix = 'st';
        break;
    case 2:
        $suffix = 'nd';
        break;
    case 3:
        $suffix = 'rd';
        break;
    default:
        $suffix = 'th';
}

echo "Today is the " . $dayPosition . $suffix . " " . $dayOfWeek . " of the month.";
// Will echo: Today is the 4th Monday of the month.

Thanks to @Jon for the maths.

answered Jan 27, 2014 at 10:36

MrUpsidownMrUpsidown

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3

Some improvements over the existing answers.

Current day of the week, simply:

echo date["N", time[]];

Day of the week for a given date:

//$date in d-m-Y, modify for your needs
function dayNumber[$date = null]     
{
    $date = $date ?? date['d-m-Y'];
    $date = DateTime::createFromFormat['d-m-Y', $date];
    return $date->format["N"];
}


echo dayNumber['24-12-2020'];

I'm using null coalescing operator [PHP 7.0 and up] and DateTime class and function [PHP 5.3.0 and up].

I would avoid using strtotime[] because of the potential time zone issues.

answered Dec 14, 2020 at 14:02