How do you check if an element is in an object javascript?

If typeof yourVariable === 'object', it's an object or null.

If you want null, arrays or functions to be excluded, just make it:

if [
    typeof yourVariable === 'object' &&
    !Array.isArray[yourVariable] &&
    yourVariable !== null
] {
    executeSomeCode[];
}

Naetmul

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answered Dec 14, 2011 at 20:40

ChuckChuck

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25

UPDATE:

This answer is incomplete and gives misleading results. For example, null is also considered of type object in JavaScript, not to mention several other edge cases. Follow the recommendation below and move on to other "most upvoted [and correct!] answer":

typeof yourVariable === 'object' && yourVariable !== null

Original answer:

Try using typeof[var] and/or var instanceof something.

EDIT: This answer gives an idea of how to examine variable's properties, but it is not a bulletproof recipe [after all there's no recipe at all!] for checking whether it's an object, far from it. Since people tend to look for something to copy from here without doing any research, I'd highly recommend that they turn to the other, most upvoted [and correct!] answer.

rap-2-h

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answered Dec 14, 2011 at 20:39

29

Let's define "object" in Javascript. According to the MDN docs, every value is either an object or a primitive:

primitive, primitive value

A data that is not an object and does not have any methods. JavaScript has 7 primitive data types: string, number, bigint, boolean, undefined, symbol, and null.

What's a primitive?

• 3
• 'abc'
• true
• null
• undefined

What's an object [i.e. not a primitive]?

• Object.prototype
• everything descended from Object.prototype
  • Function.prototype
    • Object
    • Function
    • function C[]{} -- user-defined functions
  • C.prototype -- the prototype property of a user-defined function: this is not Cs prototype
    • new C[] -- "new"-ing a user-defined function
  • Math
  • Array.prototype
    • arrays
  • {"a": 1, "b": 2} -- objects created using literal notation
  • new Number[3] -- wrappers around primitives
  • ... many other things ...
• Object.create[null]
• everything descended from an Object.create[null]

How to check whether a value is an object

instanceof by itself won't work, because it misses two cases:

// oops:  isObject[Object.prototype] -> false
// oops:  isObject[Object.create[null]] -> false
function isObject[val] {
    return val instanceof Object; 
}

typeof x === 'object' won't work, because of false positives [null] and false negatives [functions]:

// oops: isObject[Object] -> false
function isObject[val] {
    return [typeof val === 'object'];
}

Object.prototype.toString.call won't work, because of false positives for all of the primitives:

> Object.prototype.toString.call[3]
"[object Number]"

> Object.prototype.toString.call[new Number[3]]
"[object Number]"

So I use:

function isObject[val] {
    if [val === null] { return false;}
    return [ [typeof val === 'function'] || [typeof val === 'object'] ];
}

@Daan's answer also seems to work:

function isObject[obj] {
  return obj === Object[obj];
}

because, according to the MDN docs:

The Object constructor creates an object wrapper for the given value. If the value is null or undefined, it will create and return an empty object, otherwise, it will return an object of a type that corresponds to the given value. If the value is an object already, it will return the value.

A third way that seems to work [not sure if it's 100%] is to use Object.getPrototypeOf which throws an exception if its argument isn't an object:

// these 5 examples throw exceptions
Object.getPrototypeOf[null]
Object.getPrototypeOf[undefined]
Object.getPrototypeOf[3]
Object.getPrototypeOf['abc']
Object.getPrototypeOf[true]

// these 5 examples don't throw exceptions
Object.getPrototypeOf[Object]
Object.getPrototypeOf[Object.prototype]
Object.getPrototypeOf[Object.create[null]]
Object.getPrototypeOf[[]]
Object.getPrototypeOf[{}]

answered Mar 18, 2014 at 14:44

Matt FenwickMatt Fenwick

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11

underscore.js provides the following method to find out if something is really an object:

_.isObject = function[obj] {
  return obj === Object[obj];
};

UPDATE

Because of a previous bug in V8 and minor micro speed optimization, the method looks as follows since underscore.js 1.7.0 [August 2014]:

_.isObject = function[obj] {
  var type = typeof obj;
  return type === 'function' || type === 'object' && !!obj;
};

answered Feb 5, 2013 at 11:50

DaanDaan

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12

Object.prototype.toString.call[myVar] will return:

• "[object Object]" if myVar is an object
• "[object Array]" if myVar is an array
• etc.

For more information on this and why it is a good alternative to typeof, check out this article.

Ionică Bizău

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answered Nov 13, 2012 at 6:20

ChristopheChristophe

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For simply checking against Object or Array without additional function call [speed]. As also posted here.

isArray[]

isArray = function[a] {
    return [!!a] && [a.constructor === Array];
};
console.log[isArray[        ]]; // false
console.log[isArray[    null]]; // false
console.log[isArray[    true]]; // false
console.log[isArray[       1]]; // false
console.log[isArray[   'str']]; // false
console.log[isArray[      {}]]; // false
console.log[isArray[new Date]]; // false
console.log[isArray[      []]]; // true

isLiteralObject[] - Note: use for Object literals only, as it returns false for custom objects, like new Date or new YourCustomObject.

isLiteralObject = function[a] {
    return [!!a] && [a.constructor === Object];
};
console.log[isLiteralObject[        ]]; // false
console.log[isLiteralObject[    null]]; // false
console.log[isLiteralObject[    true]]; // false
console.log[isLiteralObject[       1]]; // false
console.log[isLiteralObject[   'str']]; // false
console.log[isLiteralObject[      []]]; // false
console.log[isLiteralObject[new Date]]; // false
console.log[isLiteralObject[      {}]]; // true

answered May 17, 2013 at 11:39

zupazupa

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With function Array.isArray:

function isObject[o] {
  return o !== null && typeof o === 'object' && Array.isArray[o] === false;
}

Without function Array.isArray:

Just surprised how many upvotes for wrong answers 😮
Only 1 answer passed my tests!!! Here I've created my simplified version:

function isObject[o] {
  return o instanceof Object && o.constructor === Object;
}

As for me, it's clear and simple, and just works! Here my tests:

console.log[isObject[{}]];             // Will return: true
console.log[isObject[[]]];             // Will return: false
console.log[isObject[null]];           // Will return: false
console.log[isObject[/.*/]];           // Will return: false
console.log[isObject[function [] {}]]; // Will return: false

ONE MORE TIME: not all answers pass this tests !!! 🙈

In case you need to verify that object is instance of particular class you have to check constructor with your particular class, like:

function isDate[o] {
  return o instanceof Object && o.constructor === Date;
}

simple test:

var d = new Date[];
console.log[isObject[d]]; // Will return: false
console.log[isDate[d]];   // Will return: true

As result, you will have strict and robust code!

In case you won't create functions like isDate, isError, isRegExp, etc you may consider option to use this generalized functions:

function isObject[o] {
  return o instanceof Object && typeof o.constructor === 'function';
}

it won't work correctly for all test cases mentioned earlier, but it's good enough for all objects [plain or constructed].

isObject won't work in case of Object.create[null] because of internal implementation of Object.create which is explained here but you can use isObject in more sophisticated implementation:

function isObject[o, strict = true] {
  if [o === null || o === undefined] {
    return false;
  }
  const instanceOfObject = o instanceof Object;
  const typeOfObject = typeof o === 'object';
  const constructorUndefined = o.constructor === undefined;
  const constructorObject = o.constructor === Object;
  const typeOfConstructorObject = typeof o.constructor === 'function';
  let r;
  if [strict === true] {
    r = [instanceOfObject || typeOfObject] && [constructorUndefined || constructorObject];
  } else {
    r = [constructorUndefined || typeOfConstructorObject];
  }
  return r;
};

There is already created package on npm v1 based on this implementation! And it works for all earlier described test cases! 🙂

answered Oct 10, 2017 at 9:21

cn007bcn007b

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7

Oh My God! I think this could be more shorter than ever, let see this:

Short and Final code

function isObject[obj]
{
    return obj != null && obj.constructor.name === "Object"
}

console.log[isObject[{}]] // returns true
console.log[isObject[[]]] // returns false
console.log[isObject[null]] // returns false

Explained

Return Types

typeof JavaScript objects [including null] returns "object"

console.log[typeof null, typeof [], typeof {}]

Checking on Their constructors

Checking on their constructor property returns function with their names.

console.log[[{}].constructor] // returns a function with name "Object"
console.log[[[]].constructor] // returns a function with name "Array"
console.log[[null].constructor] //throws an error because null does not actually have a property

Introducing Function.name

Function.name returns a readonly name of a function or "anonymous" for closures.

console.log[[{}].constructor.name] // returns "Object"
console.log[[[]].constructor.name] // returns "Array"
console.log[[null].constructor.name] //throws an error because null does not actually have a property

Note: As of 2018, Function.name might not work in IE //developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/name#Browser_compatibility

answered Jul 21, 2018 at 16:27

3

OK, let's give you this concept first before answering your question, in JavaScript Functions are Object, also null, Object, Arrays and even Date, so as you see there is not a simple way like typeof obj === 'object', so everything mentioned above will return true, but there are ways to check it with writing a function or using JavaScript frameworks, OK:

Now, imagine you have this object that's a real object [not null or function or array]:

var obj = {obj1: 'obj1', obj2: 'obj2'};

Pure JavaScript:

//that's how it gets checked in angular framework
function isObject[obj] {
  return obj !== null && typeof obj === 'object';
}

or

//make sure the second object is capitalised 
function isObject[obj] {
   return Object.prototype.toString.call[obj] === '[object Object]';
}

or

function isObject[obj] {
    return obj.constructor.toString[].indexOf["Object"] > -1;
}

or

function isObject[obj] {
    return obj instanceof Object;
}

You can simply use one of these functions as above in your code by calling them and it will return true if it's an object:

isObject[obj];

If you are using a JavaScript framework, they usually have prepared these kind of functions for you, these are few of them:

jQuery:

 //It returns 'object' if real Object;
 jQuery.type[obj];

Angular:

angular.isObject[obj];

Underscore and Lodash:

//[NOTE: in Underscore and Lodash, functions, arrays return true as well but not null]
_.isObject[obj];

answered Feb 15, 2017 at 13:39

AlirezaAlireza

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2

It depends on what you mean with "is an object". If you want everything that is not a primitive, i.e. things that you can set new properties on, this should do the trick:

function isAnyObject[value] {
    return value != null && [typeof value === 'object' || typeof value === 'function'];
}

It excludes the primitives [plain numbers/NaN/Infinity, plain strings, symbols, true/false, undefined and null] but should return true for everything else [including Number, Boolean and String objects]. Note that JS does not define what "host" objects, such as window or console, should return when used with typeof, so those are hard to cover with a check like this.

If you want to know whether something is a "plain" object, i.e. it was created as a literal {} or with Object.create[null], you might do this:

function isPlainObject[value] {
    if [Object.prototype.toString.call[value] !== '[object Object]'] {
        return false;
    } else {
        var prototype = Object.getPrototypeOf[value];
        return prototype === null || prototype === Object.prototype;
    }
}

Edit 2018: Because Symbol.toStringTag now allows customizing the output of Object.prototype.toString.call[...], the isPlainObject function above might return false in some cases even when the object started its life as a literal. Arguably, by convention an object with a custom string tag isn't exactly a plain object any more, but this has further muddied the definition of what a plain object even is in Javascript.

answered Jan 18, 2016 at 21:12

last-childlast-child

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2

My God, too much confusion in other answers.

Short Answer

typeof anyVar == 'object' && anyVar instanceof Object && ![anyVar instanceof Array]

To test this simply run the following statements in chrome console.

Case 1.

var anyVar = {};
typeof anyVar == 'object' && anyVar instanceof Object && ![anyVar instanceof Array] // true

Case 2.

anyVar = [];
typeof anyVar == 'object' && anyVar instanceof Object && ![anyVar instanceof Array] // false

Case 3.

anyVar = null;
typeof anyVar == 'object' && anyVar instanceof Object && ![anyVar instanceof Array]; // false

Explanation

Okay.Let's break it down

typeof anyVar == 'object' is returned true from three candidates - [], {} and null,

anyVar instanceof Object narrows down these candidates to two - [], {}

![anyVar instanceof Array] narrows to only one - {}

Drum rolls please!

By this you may have already learnt how to check for Array in Javascript.

answered Sep 24, 2018 at 11:45

HalfWebDevHalfWebDev

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2

Try this

if [objectName instanceof Object] {
  alert['Not an object'];
}
else {
  alert['An object'];
}

answered May 9, 2012 at 11:43

TalhaTalha

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4

The most reasonable way to check the type of a value seems the typeof operator. The only problem is that it's horribly broken:

• It returns "object" for null, which belongs to Null type.
• It returns "function" for callable objects, which belong to Object type.
• It can return [almost] anything it wants for non-standard non-callable objects. For example, IE seemed to like "unknown". The only forbidden results are "function" and primitive types.

typeof is only reliable for non-null primitives. So a way to check if a value is an object would be ensuring that the string returned by typeof does not correspond to a primitive, and that the object is not null. However, the problem is that a future standard could introduce a new primitive type, and our code would consider it to be an object. New types don't appear frequently, but for example ECMAScript 6 introduced the Symbol type.

Therefore, instead of typeof, I only recommend approaches whose result varies depending on if the value is an object or not. The following intends to be a

Comprehensive but not exhaustive list of proper ways to test if a value belongs to the Object type.

• Object constructor

  The Object constructor coerces the passed argument to an object. If it's already an object, the same object is returned.

  Therefore, you can use it to coerce the value to an object, and strictly compare that object with the original value.

  The following function requires ECMAScript 3, which introduced ===:

  function isObject[value] { /* Requires ECMAScript 3 or later */
    return Object[value] === value;
  }
  

  I like this approach because it's simple and self-descriptive, and an analogous check will also work for booleans, numbers and strings. However, be aware it relies on the global Object not being shadowed nor altered.

• Constructors

  When you instantiate a constructor, it can return a value different than the just-created instance. But that value will be ignored unless it's an object.

  The following function requires ECMAScript 3, which allowed constructors to return non-objects. Before ECMAScript 3 that threw an error, but try statements didn't exist back then.

  function isObject[value] { /* Requires ECMAScript 3 or later */
    return new function[] { return value; }[] === value;
  }
  

  While a bit less simple than the previous example, this one does not rely on any global property, and thus might be the safest.

• this value

  Old ECMAScript specifications required the this value to be an object. ECMAScript 3 introduced Function.prototype.call, which allowed to call a function with an arbitrary this value, but coerced to an object.

  ECMAScript 5 introduced a strict mode which removed this behavior, but in sloppy mode we still can [but arguably shouldn't] rely on it.

  function isObject[value] { /* Requires ECMAScript 3 or later in sloppy mode */
    return function[] { return this === value; }.call[value];
  }
  

• [[Prototype]]

  All ordinary objects have an internal slot called [[Prototype]], whose value determines from which other object it inherits from. The value can only be an object or null. Therefore, you can attempt to create an object which inherits from the desired value, and check if it worked.

  Both Object.create and Object.getPrototypeOf require ECMAScript 5.

  function isObject[value] { /* Requires ECMAScript 5 or later */
    try {
      Object.create[value];
      return value !== null;
    } catch[err] {
      return false;
    }
  }
  

  function isObject[value] { /* Requires ECMAScript 5 or later */
    function Constructor[] {}
    Constructor.prototype = value;
    return Object.getPrototypeOf[new Constructor[]] === value;
  }
  

• Some new ECMAScript 6 ways

  ECMAScript 6 introduces some new indirect ways to check is a value is an object. They use the previously seen approach to pass the value to some code which requires an object, wrapped inside a try statement to catch errors. Some hidden examples, not worth commenting

Note: I intentionally skipped some approaches like Object.getPrototypeOf[value] [ES5] and Reflect methods [ES6] because they call essential internal methods which might do nasty things, e.g. if value is a proxy. For safety reasons my examples only reference value without accessing it directly.

answered Aug 28, 2016 at 0:48

OriolOriol

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5

Little late... for "plain objects" [i mean, like {'x': 5, 'y': 7}] i have this little snippet:

function isPlainObject[o] {
   return [o === null || Array.isArray[o] || typeof o == 'function' || o.constructor === Date ] ?
           false
          :[typeof o == 'object'];
}

It generates the next output:

console.debug[isPlainObject[isPlainObject]]; //function, false
console.debug[isPlainObject[{'x': 6, 'y': 16}]]; //literal object, true
console.debug[isPlainObject[5]]; //number, false
console.debug[isPlainObject[undefined]]; //undefined, false
console.debug[isPlainObject[null]]; //null, false
console.debug[isPlainObject['a']]; //string, false
console.debug[isPlainObject[[]]]; //array?, false
console.debug[isPlainObject[true]]; //bool, false
console.debug[isPlainObject[false]]; //bool, false

It always works for me. If will return "true" only if the type of "o" is "object", but no null, or array, or function. :]

answered Oct 25, 2015 at 16:26

Emilio GrisolíaEmilio Grisolía

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1

Ready to use functions for checking

function isObject[o] {
  return null != o && 
    typeof o === 'object' && 
    Object.prototype.toString.call[o] === '[object Object]';
}

function isDerivedObject[o] {
  return !isObject[o] && 
    null != o && 
    [typeof o === 'object' || typeof o === 'function'] &&
    /^\[object /.test[Object.prototype.toString.call[o]];
}

// Loose equality operator [==] is intentionally used to check
// for undefined too

// Also note that, even null is an object, within isDerivedObject
// function we skip that and always return false for null

Explanation

• In Javascript, null, Object, Array, Date and functions are all objects. Although, null is bit contrived. So, it's better to check for the null first, to detect it's not null.

• Checking for typeof o === 'object' guarantees that o is an object. Without this check, Object.prototype.toString would be meaningless, since it would return object for everthing, even for undefined and null! For example: toString[undefined] returns [object Undefined]!

  After typeof o === 'object' check, toString.call[o] is a great method to check whether o is an object, a derived object like Array, Date or a function.

• In isDerivedObject function, it checks for the o is a function. Because, function also an object, that's why it's there. If it didn't do that, function will return as false. Example: isDerivedObject[function[] {}] would return false, however now it returns true.

• One can always change the definition of what is an object. So, one can change these functions accordingly.

Tests

function isObject[o] {
  return null != o && 
    typeof o === 'object' && 
    Object.prototype.toString.call[o] === '[object Object]';
}

function isDerivedObject[o] {
  return !isObject[o] && 
    null != o && 
    [typeof o === 'object' || typeof o === 'function'] &&
    /^\[object /.test[Object.prototype.toString.call[o]];
}

// TESTS

// is null an object?

console.log[
  'is null an object?', isObject[null]
];

console.log[
  'is null a derived object?', isDerivedObject[null]
];

// is 1234 an object?

console.log[
  'is 1234 an object?', isObject[1234]
];

console.log[
  'is 1234 a derived object?', isDerivedObject[1234]
];

// is new Number[1234] an object?

console.log[
  'is new Number[1234] an object?', isObject[new Number[1234]]
];

console.log[
  'is new Number[1234] a derived object?', isDerivedObject[1234]
];

// is function object an object?

console.log[
  'is [new [function []{}]] an object?', 
  isObject[[new [function []{}]]]
];

console.log[
  'is [new [function []{}]] a derived object?', 
  isObject[[new [function []{}]]]
];

// is {} an object?

console.log[
  'is {} an object?', isObject[{}]
];

console.log[
  'is {} a derived object?', isDerivedObject[{}]
];

// is Array an object?

console.log[
  'is Array an object?',
  isObject[[]]
]

console.log[
  'is Array a derived object?',
  isDerivedObject[[]]
]

// is Date an object?

console.log[
  'is Date an object?', isObject[new Date[]]
];

console.log[
  'is Date a derived object?', isDerivedObject[new Date[]]
];

// is function an object?

console.log[
  'is function an object?', isObject[function[]{}]
];

console.log[
  'is function a derived object?', isDerivedObject[function[]{}]
];

answered Nov 17, 2016 at 23:43

Inanc GumusInanc Gumus

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1

Here's an answer with optional chaining, and perhaps the smallest isObj function for this question.

const isObj = o => o?.constructor === Object;

// True for this
console.log[isObj[{}]];        // object!

// False for these
console.log[isObj[0]];         // number
console.log[isObj[[]]];        // array
console.log[isObj['lol']];     // string
console.log[isObj[null]];      // null
console.log[isObj[undefined]]; // undefined
console.log[isObj[[] => {}]];  // function
console.log[isObj[Object]];    // class

answered May 8, 2020 at 17:42

Jayant BhawalJayant Bhawal

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7

If you would like to check if the prototype for an object solely comes from Object. Filters out String, Number, Array, Arguments, etc.

function isObject [n] {
  return Object.prototype.toString.call[n] === '[object Object]';
}

Or as a single-expression arrow function [ES6+]

const isObject = n => Object.prototype.toString.call[n] === '[object Object]'

answered Apr 16, 2018 at 14:22

sasisasi

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2

var a = [1]
typeof a //"object"
a instanceof Object //true
a instanceof Array //true

var b ={a: 1}
b instanceof Object //true
b instanceof Array //false

var c = null
c instanceof Object //false
c instanceof Array //false

I was asked to provide more details. Most clean and understandable way of checking if our variable is an object is typeof myVar. It returns a string with a type [e.g. "object", "undefined"].

Unfortunately either Array and null also have a type object. To take only real objects there is a need to check inheritance chain using instanceof operator. It will eliminate null, but Array has Object in inheritance chain.

So the solution is:

if [myVar instanceof Object && ![myVar instanceof Array]] {
  // code for objects
}

answered Jun 10, 2016 at 7:41

KaniaKania

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2

lodash has isPlainObject, which might be what many who come to this page are looking for. It returns false when give a function or array.

answered Oct 20, 2014 at 19:33

PatPat

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1

Performance

Today 2020.09.26 I perform tests on MacOs HighSierra 10.13.6 on Chrome v85, Safari v13.1.2 and Firefox v80 for chosen solutions.

Results

• solutions C and H are fast/fastest on all browsers for all cases
• solutions D and G are slow/slowest on all browsers for all cases

Details

I perform 3 tests cases for solutions A B C D E F G H I J K L M N O P Q R S T U V

• for small object - you can run it HERE
• for big object - you can run it HERE
• for no object - you can run it HERE

Below snippet presents differences between solutions. Solutions A-G give proper answers for chosen cases described by Matt Fenwick

And here are example results for chrome

answered Sep 25, 2020 at 22:41

Kamil KiełczewskiKamil Kiełczewski

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The Ramda functional library has a wonderful function for detecting JavaScript types.

Paraphrasing the full function:

function type[val] {
  return val === null      ? 'Null'      :
         val === undefined ? 'Undefined' :
         Object.prototype.toString.call[val].slice[8, -1];
}

I had to laugh when I realized how simple and beautiful the solution was.

Example usage from Ramda documentation:

R.type[{}]; //=> "Object"
R.type[1]; //=> "Number"
R.type[false]; //=> "Boolean"
R.type['s']; //=> "String"
R.type[null]; //=> "Null"
R.type[[]]; //=> "Array"
R.type[/[A-z]/]; //=> "RegExp"
R.type[[] => {}]; //=> "Function"
R.type[undefined]; //=> "Undefined"

answered Feb 22, 2018 at 21:34

DaveGauerDaveGauer

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After reading and trying out a lot of implementations, I've noticed that very few people try to check for values like JSON, Math, document or objects with prototype chains longer than 1 step.

Instead of checking the typeof of our variable and then hacking away edge-cases, I thought it'd be better if the check is kept as simple as possible to avoid having to refactor when there's new primitives or native objects added that register as typeof of 'object'.

After all, the typeof operator will tell you if something is an object to JavaScript, but JavaScript's definition of an object is too broad for most real-world scenarios [e.g. typeof null === 'object']. Below is a function that determines whether variable v is an object by essentially repeating two checks:

1. A loop is started that continues as long as the stringified version of v is '[object Object]'.
   I wanted the result of the function to be exactly like the logs below, so this is the only "objectness"-criteria I ended up with. If it fails, the function returns false right away.
2. v is replaced with the next prototype in the chain with v = Object.getPrototypeOf[v], but also directly evaluated after. When the new value of v is null, it means that every prototype including the root prototype [which could very well have been the only prototype inside the chain] have passed the check in the while loop and we can return true. Otherwise, a new iteration starts.

function isObj [v] {
  while [     Object.prototype.toString.call[v] === '[object Object]']
  if    [[v = Object.getPrototypeOf[v]]         === null]
  return true
  return false
}

console.log['FALSE:']
console.log['[]                   -> ', isObj[[]]]
console.log['null                 -> ', isObj[null]]
console.log['document             -> ', isObj[document]]
console.log['JSON                 -> ', isObj[JSON]]
console.log['function             -> ', isObj[function [] {}]]
console.log['new Date[]           -> ', isObj[new Date[]]]
console.log['RegExp               -> ', isObj[/./]]

console.log['TRUE:']
console.log['{}                   -> ', isObj[{}]]
console.log['new Object[]         -> ', isObj[new Object[]]]
console.log['new Object[null]     -> ', isObj[new Object[null]]]
console.log['new Object[{}]       -> ', isObj[new Object[{foo: 'bar'}]]]
console.log['Object.prototype     -> ', isObj[Object.prototype]]
console.log['Object.create[null]  -> ', isObj[Object.create[null]]]
console.log['Object.create[{}]    -> ', isObj[Object.create[{foo: 'bar'}]]]
console.log['deep inheritance     -> ', isObj[Object.create[Object.create[{foo: 'bar'}]]]]

answered Sep 10, 2019 at 2:11

Gust van de WalGust van de Wal

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When everything else fails, I use this:

var isObject = function[item] {
   return item.constructor.name === "Object";
}; 

answered Sep 18, 2014 at 18:42

MichalMichal

1311 silver badge1 bronze badge

5

This will work. It is a function that returns true, false, or possibly null.

const isObject = obj => obj && obj.constructor && obj.constructor === Object;

console.log[isObject[{}]]; // true
console.log[isObject[[]]]; // false
console.log[isObject[new Function]]; // false
console.log[isObject[new Number[123]]]; // false
console.log[isObject[null]]; // null

answered Apr 5, 2017 at 6:41

pizzarobpizzarob

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1

Since there seems a lot of confusion about how to handle this problem correctly, I'll leave my 2 cents [this answer is spec compliant and produces correct results under all circumstances]:

Testing for primitives: undefined null boolean string number

function isPrimitive[o]{return typeof o!=='object'||null}

An object is not a primitive:

function isObject[o]{return !isPrimitive[o]}

Or alternatively:

function isObject[o]{return o instanceof Object}
function isPrimitive[o]{return !isObject[o]}

Testing for any Array:

const isArray=[function[]{
    const arrayTypes=Object.create[null];
    arrayTypes['Array']=true;
    arrayTypes['Int8Array']=true;
    arrayTypes['Uint8Array']=true;
    arrayTypes['Uint8ClampedArray']=true;
    arrayTypes['Int16Array']=true;
    arrayTypes['Uint16Array']=true;
    arrayTypes['Int32Array']=true;
    arrayTypes['Uint32Array']=true;
    arrayTypes['BigInt64Array']=true;
    arrayTypes['BigUint64Array']=true;
    arrayTypes['Float32Array']=true;
    arrayTypes['Float64Array']=true;
    return function[o]{
        if [!o] return false;
        return !isPrimitive[o]&&!!arrayTypes[o.constructor.name];
    }
}[]];

Testing for object excluding: Date RegExp Boolean Number String Function any Array

const isObjectStrict=[function[]{
    const nativeTypes=Object.create[null];
    nativeTypes['Date']=true;
    nativeTypes['RegExp']=true;
    nativeTypes['Boolean']=true;
    nativeTypes['Number']=true;
    nativeTypes['String']=true;
    nativeTypes['Function']=true;
    return function[o]{
        if [!o] return false;
        return !isPrimitive[o]&&!isArray[o]&&!nativeTypes[o.constructor.name];
    }
}[]];

answered Nov 12, 2018 at 14:06

c7x43tc7x43t

2642 silver badges5 bronze badges

For the purpose of my code I found out this decision which corresponds with some of the answers above:

ES6 variant:

const checkType = o => Object.prototype
                    .toString
                    .call[o]
                    .replace[/\[|object\s|\]/g, '']
                    .toLowerCase[];

ES5 variant:

function checkType[o]{
   return Object.prototype
                    .toString
                    .call[o]
                    .replace[/\[|object\s|\]/g, '']
                    .toLowerCase[];
}

You can use it very simply:

checkType[[]] === 'array'; // true
checkType[{}] === 'object'; // true
checkType[1] === 'number'; // true
checkType[''] === 'string'; // true
checkType[{}.p] === 'undefined'; // true
checkType[null] === 'null'; // true

and so on..

answered Jun 23, 2020 at 10:29

ChristiyanChristiyan

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2

const isObject = function[obj] {
  const type = typeof obj;
  return type === 'function' || type === 'object' && !!obj;
};

!!obj is shorthand for checking if obj is truthy [to filter out null]

answered Dec 16, 2014 at 0:49

IraIra

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It is an old question but thought to leave this here. Most people are checking if the variable is {} meaning a key-value paired and not what is the underline construct that JavaScript is using for a given thing, cuz to be honest mostly everything in JavaScript is an object. So taking that out of the way. If you do...

let x = function[] {}
typeof x === 'function' //true
x === Object[x] // true
x = []
x === Object[x] // true

// also
x = null
typeof null // 'object'

Most of the time what we want is to know if we have a resource object from an API or our database call returned from the ORM. We can then test if is not an Array, is not null, is not typeof 'function', and is an Object

// To account also for new Date[] as @toddmo pointed out

x instanceof Object && x.constructor === Object

x = 'test' // false
x = 3 // false
x = 45.6 // false
x = undefiend // false
x = 'undefiend' // false
x = null // false
x = function[]{} // false
x = [1, 2] // false
x = new Date[] // false
x = {} // true

answered Nov 27, 2019 at 18:28

redeemefyredeemefy

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2

function isObjectLike[value] {
  return value != null && typeof value == 'object' && !Array.isArray[value];
}

Based from lodash

answered Apr 12, 2020 at 21:48

insigninsign

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1

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