How do you find the sum of odd digits in python?

The following article shows how given an integer list, we can produce the sum of all its odd and even digits.

Input : test_list = [345, 893, 1948, 34, 2346] 
Output : 
Odd digit sum : 36 
Even digit sum : 40 
Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.
Input : test_list = [345, 893] 
Output : 
Odd digit sum : 20 
Even digit sum : 12 
Explanation : 4 + 8 = 12, even summation. 

Method 1 : Using loop, str[] and int[]

In this, we first convert each element to string and then iterate for each of its element, and add to respective summation by conversion to integer.

Python3

test_list = [345, 893, 1948, 34, 2346]

print["The original list is : " + str[test_list]]

odd_sum = 0

even_sum = 0

for sub in test_list:

    for ele in str[sub]:

        if int[ele] % 2 == 0:

            even_sum += int[ele]

        else:

            odd_sum += int[ele]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

The original list is : [345, 893, 1948, 34, 2346]
Odd digit sum : 36
Even digit sum : 40

Method 2: Using loop and sum[]

In this, we perform task of getting summation using sum[], and loop is used to perform the task of iterating through each element.

Python3

test_list = [345, 893, 1948, 34, 2346]

print["The original list is : " + str[test_list]]

odd_sum = 0

even_sum = 0

for sub in test_list:

    odd_sum += sum[[int[ele] for ele in str[sub] if int[ele] % 2 == 1]]

    even_sum += sum[[int[ele] for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

The original list is : [345, 893, 1948, 34, 2346]
Odd digit sum : 36
Even digit sum : 40

Method 3: Using list comprehension 

Python3

test_list = [345, 893, 1948, 34, 2346]

odd_sum = 0

even_sum = 0

odd_sum += sum[[int[ele]

                for sub in test_list for ele in str[sub] if int[ele] % 2 == 1]]

even_sum += sum[[int[ele]

                 for sub in test_list for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

Odd digit sum : 36
Even digit sum : 40

Method 4: Using the enumerate function

Python3

test_list = [345, 893, 1948, 34, 2346]

odd_sum = 0

even_sum = 0

odd_sum += sum[[int[ele] for i, sub in enumerate[test_list]

                for ele in str[sub] if int[ele] % 2 == 1]]

even_sum += sum[[int[ele] for i, sub in enumerate[test_list]

                 for ele in str[sub] if int[ele] % 2 == 0]]

print["Odd digit sum : " + str[odd_sum]]

print["Even digit sum : " + str[even_sum]]

Output

Odd digit sum : 36
Even digit sum : 40


How do you find the sum of odd numbers in Python?

Use the following steps to find or calculate sum of odd number from 1 to n in python:.
Take the input number from 1 to that user-entered value..
Define a variable, which name total..
Iterate for loop and check each number using num%2 != ... .
If the number is odd, so add the number into total variable..
Print the sum of odd number..

How do you find the sum of digits in an odd place?

Approach:.
First, calculate the reverse of the given number..
To the reverse number we apply modulus operator and extract its last digit which is actually the first digit of a number so it is odd positioned digit..
The next digit will be even positioned digit, and we can take the sum in alternating turns..

How do you find the sum of even and odd numbers in Python?

Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation. Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.

How do you find the sum of odd and even numbers?

Sum of an even number and an odd number is always an odd number.

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