Hướng dẫn php undefined index check
The isset() function does not check if a variable is defined.It seems you've specifically stated that you're not looking for Show
It's important to realize in programming that null is something. I don't know why it was decided that To check if a variable is
undefined you will have to check if the variable is in the list of defined variables, using In the following example it will work the same way as JavaScript's undefined check.
But in this example, it won't work like JavaScript's undefined check.
So how do you actually check if a variable is defined? You check the defined variables.Using
However, if you're finding that in your code you have to check for whether a variable has been defined or not, then you're likely doing something wrong. This is my personal
belief as to why the core PHP developers left The ternary expression:
is OK when used stand-alone like this:
because it is equivalent to the expected:
but, when used in string concatenation then you need parenthesis in order to confine the scope of the comparison so that the leading string is not part of the comparison
Doing (wrong way):
is equivalent to
In conclusion: When in doubt, add parenthesis. When not in doubt, add parenthesis anyways because the code will be more legible when you have to re-visit it in 6 months. Most text editors have parenthesis and bracket match highlighting so adding parenthesis is a very beneficial way to declare and later see the operation's intended behavior. See Operator Precedence if you come across someone's cryptic code and need help figuring out what on Earth they were thinking and/or failed to consider. PHP is a widely used scripting language that is mainly used for web development purposes. It is a scripting language and finds application in automating tasks that would otherwise be impossible to implement with just human intervention. Being a server-side language, it primarily takes care of things at the server’s end.
Launched in 1995 for public use, it has remained a popular choice among web developers since then. Programming is a tricky business. It is pretty normal to stumble upon errors and warnings while making a program.
The same happens a lot to PHP developers, like when they face an Undefined index in PHP. However, such errors are not hard to deal with with a little bit of knowledge and guidance. Websites often use forms to collect data from visitors. PHP uses $GET and
$POST methods for such data collection. This data is collected and saved in variables that are used by the website to work and serve the visitor further. Many a time, some fields are left blank by the user. But the website tries to refer to
these fields for proceeding further. That means the PHP code tries to get the value of the field that no one has defined and thus does not exist. Quite expectedly, it does not work and raises a notice called Undefined Index in PHP. $name = $_GET['name']; $age = $_GET['age']; $grade = $_GET[‘grade’]; echo 'Name: '.$name; echo ' echo ‘ ?> You can fix it
using the isset() function, which we will discuss further in the upcoming sections. Undefined Index is a notice in PHP, and it is a choice of the developer to either ignore it or fix it. Undefined Index in PHP is a Notice generated by the language. The simplest way to ignore such a notice is to ask PHP to stop generating such notices. You can either add a small line of
code at the top of the PHP page or edit the field error_reporting in the php.ini file. 1. Adding Code at the Top of the PageA simple way to ask PHP to disable reporting of notices is to put a line of code at the beginning of the PHP page. Code:
Or you can add the following code which stops all the error reporting,
2. Changes in php.iniPhp.ini is a configuration file and is essential for all the programs running on PHP. Open this file and find the field error_reporting. The easiest way is to use the ctrl + F shortcut key. By default, error reporting is set to E_ALL. That means all errors are reported. Change this to E_ALL & ~E_NOTICE. It means all errors except for the notices will now be reported. How to Fix the PHP Notice: Undefined Index?We know the cause of the error. It occurs when we use $_GET and $_POST methods to get input, but we reference it even when it has not been set. The solution simply is to check if it has been set before referencing. We can use the isset() function, which checks if the variable ‘is set’ or not before referencing to them. Isset() function returns True or False depending on it. Undefined Index in PHP $_GETWhen using the $_GET method, the following code might show the notice Undefined index in PHP: Code:$name = $_GET[‘name’]; $age = $_GET[‘age’]; $grade = $_GET[‘grade’]; echo 'Name: '.$name; echo ' echo ' ?> As we have not set any of these variables, this code shows the Undefined Index notice. Change it to the following code to fix this issue: Code:if(isset($_GET['name'])){ $name = $_GET['name']; }else{ $name = " John - This is our default name"; } if(isset($_GET['age'])){ $age = $_GET['age']; }else{ $age = "10 - This is our default age. Let's leave the grade blank."; } if(isset($_GET['grade'])){ $grade = $_GET['grade']; }else{ $grade = ""; } echo 'Name: '.$name; echo
' echo ' ?> Result:We can use a single line of code like this instead. Code:$name = isset($_GET[‘name’]) ? $_GET[‘name’]: “John- This is our default name”; Echo ‘Name: ‘.$name; ?> This approach also achieves the intended goal. Result:Notice: Undefined Variable PHP shows this notice when we try to use a variable even before defining it. Code:$echo $name; Result:It can be solved either by declaring a variable global and then using isset() to see if it is set or not. It can be echoed only if it has been set. Alternatively, we can use isset(X) ? Y to set a default. Code:global $name; if(isset($name)) { echo $name; } ?> Result:We can set it after the isset() check like this. Code:$name= isset($name) ? $name:"Default"; echo $name; ?> Result: Notice: Undefined Offset It shows Undefined Offset Notice in PHP when we are referring to a key in an array that has not been set for the array. Here’s an example. Code:$nameArray = array(1=>'one', 2=>'two', 4=>'four'); echo $nameArray[3]; ?> Result:It might show an undefined array key warning for some. It means the same thing that you are trying to access an undefined array key. It can be solved similarly like the last two cases by using isset(), arrayexists() or empty() function. Code:$nameArray = array(1=>'one', 2=>'two', 4=>'four'); echo 'using isset()'; echo ' if(isset($nameArray[3])) {echo $nameArray[3]; } echo 'key 1 if(isset($nameArray[1])) {echo $nameArray[1]; } echo ' echo 'key 3 echo array_key_exists(3, $nameArray); echo ' echo array_key_exists(2, $nameArray); echo ' echo 'key 3 if(!empty($nameArray[3])) {echo $nameArray[3]; } echo ' if(!empty($nameArray[4])) {echo $nameArray[4]; } ?> Result:Master front-end and back-end technologies and advanced aspects in our Post Graduate Program in Full Stack Web Development. Unleash your career as an expert full stack developer. Get in touch with us NOW! ConclusionIn this article, we learned about the undefined index in PHP. However, it is just one of the many errors, warnings, and notices that a PHP developer has to deal with. If you are looking to make a career out of developing web applications and handling such errors, Simplilearn is offering a Post Graduate program in Full stack web development, in partnership with Caltech CTME. Simplilearn is the world’s #1 online Bootcamp that has helped advance 2,000,000 careers through collaboration with World’s top-ranking universities. |