Php search in array multiple values

I need to get the keys from values that are duplicates. I tried to use array_search and that worked fine, BUT I only got the first value as a hit.

I need to get both keys from the duplicate values, in this case 0 and 2. The search result output as an array would be good.

Is there a PHP function to do this or do I need to write some multiple loops to do it?

$list[0][0] = "2009-09-09";
$list[0][1] = "2009-05-05";
$list[0][2] = "2009-09-09";
$list[1][0] = "first-paid";
$list[1][1] = "1";
$list[1][2] = "last-unpaid";

echo array_search("2009-09-09",$list[0]);

kenorb

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asked Jul 31, 2009 at 13:42

Jens TörnellJens Törnell

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You want array_keys with the search value

array_keys($list[0], "2009-09-09");

which will return an array of the keys with the specified value, in your case [0, 2]. If you want to find the duplicates as well, you can first make a pass with array_unique, then iterate over that array using array_keys on the original; anything which returns an array of length > 1 is a duplicate, and the result is the keys in which the duplicates are stored. Something like...

$uniqueKeys = array_unique($list[0])

foreach ($uniqueKeys as $uniqueKey)
{
  $v = array_keys($list[0], $uniqueKey);

  if (count($v) > 1)
  {
    foreach ($v as $key)
    {
      // Work with $list[0][$key]
    }

  }
}

answered Jul 31, 2009 at 13:46

Adam WrightAdam Wright

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2

In array_search() we can read:

If needle is found in haystack more than once, the first matching key is returned. To return the keys for all matching values, use array_keys() with the optional search_value parameter instead.

kenorb

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answered Jul 31, 2009 at 13:46

1

The following combination of function calls will give you all duplicate values:

$a = array(1, 1, 2, 3, 4, 5, 99, 2, 5, 2);

$unique     = array_unique($a); // preserves keys
$diffkeys   = array_diff_key($a, $unique);
$duplicates = array_unique($diffkeys);

echo 'Duplicates: ' . join(' ', $duplicates) . "\n"; // 1 2 5

answered Jul 31, 2009 at 14:31

Till TheisTill Theis

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You can achieve that using array_search() by using while loop and the following workaround:

while (($key = array_search("2009-09-09", $list[0])) !== FALSE) {
  print($key);
  unset($list[0][$key]);
}

Source: cue at openxbox at php.net

For one-multidimensional array, you may use the following function to achieve that (as alternative to array_keys()):

function array_isearch($str, $array){
  $found = array();
  foreach ($array as $k => $v) {
    if (strtolower($v) == strtolower($str)) {
      $found[] = $k;
    }
  }
  return $found;
}

Source: robertark, php.net

answered Nov 8, 2015 at 19:07

kenorbkenorb

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0

$userdb=Array
(
    (0) => Array
        (
            (uid) => '100',
            (name) => 'Sandra Shush',
            (url) => 'urlof100'
        ),
);

$key = array_search(100, array_column($userdb, 'uid'));

Sven Eberth

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answered Jun 19, 2021 at 11:10

1

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