Sum of 21 and 62 in python

Python String: Exercise-62 with Solution

Write a Python program to compute sum of digits of a given string.

Sample Solution:-

Python Code:

def sum_digits_string[str1]:
    sum_digit = 0
    for x in str1:
        if x.isdigit[] == True:
            z = int[x]
            sum_digit = sum_digit + z

    return sum_digit
     
print[sum_digits_string["123abcd45"]]
print[sum_digits_string["abcd1234"]]

Sample Output:

15
10

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Given a number and the task is to find sum of digits of this number in Python. 
Examples: 
 

Input : n = 87 
Output : 15 
Input : n = 111 
Output : 3

 
Below are the methods to sum of the digits. 
Method-1: Using str[] and int[] methods.: The str[] method is used to convert the number to string. The int[] method is used to convert the string digit to an integer. 

Convert the number to string and iterate over each digit in the string and after converting each digit to integer and add to the sum of the digits in each iteration. 

Python3

def getSum[n]:

    sum = 0

    for digit in str[n]: 

      sum += int[digit]      

    return sum

n = 12345

print[getSum[n]]

Output:

15

Method-2: Using sum[] methods.: The sum[] method is used to sum of numbers in the list.

Convert the number to string using str[] and strip the string and convert to list of number using strip[] and map[] method resp. Then find the sum using the sum[] method.

Python3

def getSum[n]:

    strr = str[n]

    list_of_number = list[map[int, strr.strip[]]]

    return sum[list_of_number]

n = 12345

print[getSum[n]]

Output:

15

Method-3: Using General Approach: 

• Get the number
• Declare a variable to store the sum and set it to 0
• Repeat the next two steps till the number is not 0
• Get the rightmost digit of the number with help of remainder ‘%’ operator by dividing it with 10 and add it to sum.
• Divide the number by 10 with help of ‘//’ operator
• Print or return the sum

A. Iterative Approach:

Python3

def getSum[n]:

    sum = 0

    while [n != 0]:

        sum = sum + [n % 10]

        n = n//10

    return sum

n = 12345

print[getSum[n]]

Output:

15

B. Recursive Approach:

Python3

def sumDigits[no]:

    return 0 if no == 0 else int[no % 10] + sumDigits[int[no / 10]] 

n = 12345

print[sumDigits[n]]

Output:

15