Var_dump to log file php

Writing objects to the PHP error log using error_log() can be useful, but it isn’t allowed – you can only write strings there. What to do?

Well, luckily there are options for both print_r() – human friendly – and var_dump() – parseable – that will let you convert an object into a string.

Use print_r()

Using print_r() is the easiest, since the second parameter to the function says that we want to send the output to a variable rather than echoing it. Thus, to write to the error_log you just need to use the following code.

$object = new MyObject();
error_log( print_r( $object, true ) );

Use var_dump()

If you want the more detailed output of var_dump(), it’s a bit trickier, but still pretty easy. In a nutshell, since you can only echo the results you have to capture the output buffer with ob_start(), assign it to a variable, and then clean the buffer with ob_end_clean() allowing you to write the resulting variable to the error_log.

function var_error_log( $object=null ){
    ob_start();                    // start buffer capture
    var_dump( $object );           // dump the values
    $contents = ob_get_contents(); // put the buffer into a variable
    ob_end_clean();                // end capture
    error_log( $contents );        // log contents of the result of var_dump( $object )
}

$object = new MyObject();
var_error_log( $object );

I have the php code for sql query

> " .$server ;
		
		$result = mysql_query('SHOW DATABASES');
        echo "
";
        while ($row = mysql_fetch_array($result))
        {
            var_dump ($row); }
	    }
    }
    ini_set('max_execution_time', 10);
    return $link;
?>

this code print my database name on the browser how I can save the database name into text file

Connected successfully to >> 127.0.0.1
array(2) { [0]=> string(18) "information_schema" ["Database"]=> string(18) "information_schema" } array(2) { [0]=> string(2) "db" ["Database"]=> string(2) "db" } array(2) { [0]=> string(5) "mysql" ["Database"]=> string(5) "mysql" } array(2) { [0]=> string(10) "phpmyadmin" ["Database"]=> string(10) "phpmyadmin" } array(2) { [0]=> string(4) "test" ["Database"]=> string(4) "test" }

RiggsFolly

90.8k20 gold badges101 silver badges145 bronze badges

asked Aug 12, 2016 at 23:15

4

You can use the output buffering functions to capture output and write it to a file.

ob_flush();
ob_start();
while ($row = mysql_fetch_assoc($result)) {
    var_dump($row);
}
file_put_contents("dump.txt", ob_get_flush());

answered Aug 12, 2016 at 23:25

8

Don't use var_dump for this, use serialize like so:

To restore it, you can use unserialize($filecontents); by reading it back in from the file.

answered Aug 12, 2016 at 23:25

1

> " .$server ;

        $result = mysql_query('SHOW DATABASES');
echo "
";
while ($row = mysql_fetch_array($result))
{
fwrite($rez, $row['DatabaseName']); }

    }

}
ini_set('max_execution_time', 10);
return $link;
    ?>

answered Aug 12, 2016 at 23:29

This should work

$file = 'somefile.txt';
file_put_contents($file, $some_var);

You may want to serialize the variable first to make it more readable.

But there are several other methods: http://php.net/manual/en/function.file-put-contents.php

answered Aug 12, 2016 at 23:19

AndyAndy

1021 silver badge4 bronze badges

What is the purpose of Var_dump () in PHP?

What does Var_dump return?

What is the difference between Var_dump () and Print_r ()?

What value will Var_dump show?