Remove id from object javascript

Using delete:

delete selectedMap[event.target.id];

You're setting the value incorrectly, though. Here's the correct way:

if[event.target == true]{
    var key = event.target.id;   //  obj.id === id];
  arr.splice[objWithIdIndex, 1];

  return arr;
}

const arr = [
  { id: 1, name: 'John' },
  { id: 2, name: 'Kate' },
  { id: 3, name: 'Peter' },
];

removeObjectWithId[arr, 2];

// [ { id: 1, name: 'John' }, { id: 3, name: 'Peter' } ]
console.log[arr];

The Array findIndex[] method returns the index of the first element in an array that passes a test specified by a callback function.

const arr = [9, 8, 7, 6, 5];

const index = arr.findIndex[[num] => num === 7];
console.log[index]; // 2

We specify a test that an object in that array will pass only if it has an ID equal to the specified ID. This makes findIndex[] return the index of the object with that ID.

The Array splice[] method changes the contents of an array by removing existing elements while adding new ones simultaneously.

const arr1 = ['a', 'b', 'c'];

// Removing elements
arr1.splice[1, 2];
console.log[arr1]; // [ 'a' ]

// Removing and adding new elements
const arr2 = ['a', 'b', 'c'];
arr2.splice[1, 2, 'd', 'e'];
console.log[arr2]; // [ 'a', 'd', 'e' ]

This method takes three arguments:

  1. start – the index at which to start changing the array.
  2. deleteCount – the number of elements to remove from start
  3. item1, item2, ... – a variable number of elements to add to the array, beginning from start.

We specify a deleteCount of 1 and a start of the target index to make splice[] remove just the object with that index from the array. We didn’t specify any more arguments, so nothing is added to the array.

Avoiding Side Effects

The Array splice[] method mutates the passed array. This introduces a side effect into our removeObjectWithId[] function. To avoid modifying the passed array and create a pure function, make a copy of the array and call splice[] on the copy, instead of the original

function removeObjectWithId[arr, id] {
  // Making a copy with the Array from[] method
  const arrCopy = Array.from[arr];

  const objWithIdIndex = arrCopy.findIndex[[obj] => obj.id === id];
  arrCopy.splice[objWithIdIndex, 1];
  return arrCopy;
}

const arr = [
  { id: 1, name: 'John' },
  { id: 2, name: 'Kate' },
  { id: 3, name: 'Peter' },
];

const newArr = removeObjectWithId[arr, 2];

// [ { id: 1, name: 'John' }, { id: 3, name: 'Peter' } ]
console.log[newArr];

// original not modified
/**
[
  { id: 1, name: 'John' },
  { id: 2, name: 'Kate' },
  { id: 3, name: 'Peter' }
]
 */
console.log[arr];

Tip

Functions that don’t modify external state [i.e., pure functions] tend to be more predictable and easier to reason about. This makes it a good practice to limit the number of side effects in your programs.

2. The Array filter[] Method

We can also remove an element from an array by ID with the filter[] method. We call filter[] on the array, passing a callback that returns true for every element in that array apart from the object with the specified ID.

Example

function removeObjectWithId[arr, id] {
  return arr.filter[[obj] => obj.id !== id];
}

const arr = [
  { id: 1, name: 'John' },
  { id: 2, name: 'Kate' },
  { id: 3, name: 'Peter' },
];

const newArr = removeObjectWithId[arr, 2];

// [ { id: 1, name: 'John' }, { id: 3, name: 'Peter' } ]
console.log[newArr];

// original not modified
/**
[
  { id: 1, name: 'John' },
  { id: 2, name: 'Kate' },
  { id: 3, name: 'Peter' }
]
 */
console.log[arr];

The Array filter[] method creates a new array filled with elements that pass a test specified by a callback function. It does not modify the original array.

Example

const arr = [1, 2, 3, 4];

const filtered = arr.filter[[num] => num > 2];
console.log[filtered]; // [ 3, 4 ]

In our example, we set a test that an object in the array will pass only if its id property is not equal to the specified ID. This ensures that the object with the specified ID is not included in the new array returned from filter[].

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Ayibatari Ibaba is a software developer with years of experience building websites and apps. He has written extensively on a wide range of programming topics and has created dozens of apps and open-source libraries.

How do I remove a property from an object?

Remove Property from an Object The delete operator deletes both the value of the property and the property itself. After deletion, the property cannot be used before it is added back again. The delete operator is designed to be used on object properties. It has no effect on variables or functions.

How do you remove an ID from an array?

To remove an element from an array by ID in JavaScript, use the findIndex[] method to find the index of the object with the ID in the array. Then call the splice[] method on the array, passing this index and 1 as arguments to remove the object from the array.

How do you remove an object in JavaScript?

The only way to fully remove the properties of an object in JavaScript is by using delete operator. If the property which you're trying to delete doesn't exist, delete won't have any effect and can return true.

How do you delete an element?

Removing an element using the removeChild[] method First, select the target element that you want to remove using DOM methods such as querySelector[] . Then, select the parent element of the target element and use the removeChild[] method.

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