How could I go about finding the division remainder of a number in Python?
For example:
If the number is 26 and divided number is 7, then the division remainder is 5.
[since 7+7+7=21 and 26-21=5.]
asked Apr 7, 2011 at 16:44
1
you are looking for the modulo operator:
a % b
for example:
>>> 26 % 7
5
Of course, maybe they wanted you to implement it yourself, which wouldn't be too difficult either.
wjandrea
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answered Apr 7, 2011 at 16:45
Uku LoskitUku Loskit
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The remainder of a division can be discovered using the operator %:
>>> 26%7
5
In case you need both the quotient and the modulo, there's the builtin divmod function:
>>> seconds= 137
>>> minutes, seconds= divmod[seconds, 60]
answered May 1, 2011 at 11:49
tzottzot
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26 % 7 [you will get remainder]
26 / 7 [you will get divisor, can be float value]
26 // 7 [you will get divisor, only integer
value]
wjandrea
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answered Mar 17, 2016 at 22:14
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If you want to get quotient and remainder in one line of code [more general usecase], use:
quotient, remainder = divmod[dividend, divisor]
#or
divmod[26, 7]
answered Feb 21, 2019 at 4:44
Alok NayakAlok Nayak
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From Python 3.7, there is a new math.remainder[] function:
from math import remainder
print[remainder[26,7]]
Output:
-2.0 # not 5
Note, as above,
it's not the same as %.
Quoting the documentation:
math.remainder[x, y]
Return the IEEE 754-style remainder of x with respect to y. For finite x and finite nonzero y, this is the difference x - n*y, where n is the closest integer to the exact value of the quotient x / y. If x / y is exactly halfway between two consecutive integers, the nearest even integer is used for n. The remainder r = remainder[x, y] thus always satisfies abs[r]