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Given a list of numbers, write a Python program to print all even numbers in the given list.
Example:
Input: list1 = [2, 7, 5, 64, 14] Output: [2, 64, 14]
Input: list2 = [12, 14, 95, 3] Output: [12, 14]
Method 1: Using for loop
Iterate each element in the list using for loop and check if num % 2 == 0. If the condition satisfies, then only print the number.
Python3
list1 = [10, 21, 4, 45, 66, 93]
for num in list1:
if
num % 2 == 0:
print[num, end=" "]
Output:
10, 4, 66
Method 2: Using while loop
Python3
list1 = [10, 24, 4, 45, 66, 93]
num =
0
while[num < len[list1]]:
if list1[num] % 2 == 0:
print[list1[num], end=" "]
num += 1
Output:
10, 4, 66
Method 3: Using list comprehension
Python3
list1 = [10, 21, 4, 45, 66, 93]
even_nos = [num for num in list1 if num % 2 == 0]
print["Even numbers in the list: ", even_nos]
Output:
Even numbers in the list: [10, 4, 66]
Method 4: Using lambda expressions
Python3
list1 = [10, 21, 4, 45, 66, 93, 11]
even_nos = list[filter[lambda x: [x % 2 == 0], list1]]
print["Even numbers in the list: ", even_nos]
Output
Even numbers in the list: [10, 4, 66]
Method 5: Using Recursion
Python3
def evennumbers[list, n=0]:
if n==len[list]:
exit[]
if list[n]%2==0:
print[list[n], end=" "]
evennumbers[list, n+1]
list1 = [10, 21, 4, 45, 66, 93]
print["Even numbers in the list:", end=" "]
evennumbers[list1]
Output
Even numbers in the list: 10 4 66
Method: Using enumerate function
Python3
list1 =
[2, 7, 5, 64, 14]
for a,i in enumerate[list1]:
if i%2==0:
print[i,end=" "]
Method: Using pass
Python3
list1 =
[2, 7, 5, 64, 14]
for i in list1:
if i%2!=0:
pass
else:
print[i,end=" "]
Auxiliary Space: O[1]