Php read text file into array

I am trying to read every line of a text file into an array and have each line in a new element.
My code so far.

asked May 28, 2011 at 4:40

3

If you don't need any special processing, this should do what you're looking for

$lines = file[$filename, FILE_IGNORE_NEW_LINES];

answered May 28, 2011 at 4:48

Yanick RochonYanick Rochon

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2

The fastest way that I've found is:

// Open the file
$fp = @fopen[$filename, 'r']; 

// Add each line to an array
if [$fp] {
   $array = explode["\n", fread[$fp, filesize[$filename]]];
}

where $filename is going to be the path & name of your file, eg. ../filename.txt.

Depending how you've set up your text file, you'll have might have to play around with the \n bit.

Peter Stuart

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answered Jan 2, 2012 at 19:37

2

Just use this:

$array = explode["\n", file_get_contents['file.txt']];

answered Apr 5, 2013 at 11:15

RoLifeRoLife

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0

$yourArray = file["pathToFile.txt", FILE_IGNORE_NEW_LINES];

FILE_IGNORE_NEW_LINES avoid to add newline at the end of each array element
You can also use FILE_SKIP_EMPTY_LINES to Skip empty lines

reference here

answered Apr 15, 2015 at 18:46

answered May 28, 2011 at 4:45

GauravGaurav

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3

It's just easy as that:

$lines = explode["\n", file_get_contents['foo.txt']];

file_get_contents[] - gets the whole file as string.

explode["\n"] - will split the string with the delimiter "\n" - what is ASCII-LF escape for a newline.

But pay attention - check that the file has UNIX-Line endings.

If "\n" will not work properly you have another coding of newline and you can try "\r\n", "\r" or "\025"

answered Mar 21, 2014 at 16:17

CodeBrauerCodeBrauer

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$lines = array[];
while [[$line = fgets[$file]] !== false]
    array_push[$lines, $line];

Obviously, you'll need to create a file handle first and store it in $file.

answered May 28, 2011 at 4:45

Rafe KettlerRafe Kettler

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$file = __DIR__."/file1.txt";
$f = fopen[$file, "r"];
$array1 = array[];

while [ $line = fgets[$f, 1000] ]
{
    $nl = mb_strtolower[$line,'UTF-8'];
    $array1[] = $nl;
}

print_r[$array];

answered Dec 1, 2013 at 13:28

0

You were on the right track, but there were some problems with the code you posted. First of all, there was no closing bracket for the while loop. Secondly, $line_of_text would be overwritten with every loop iteration, which is fixed by changing the = to a .= in the loop. Third, you're exploding the literal characters '\n' and not an actual newline; in PHP, single quotes will denote literal characters, but double quotes will actually interpret escaped characters and variables.

answered May 30, 2011 at 5:24

Nick AndrenNick Andren

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    $file = file["links.txt"];
print_r[$file];

This will be accept the txt file as array. So write anything to the links.txt file [use one line for one element] after, run this page :] your array will be $file

answered Mar 22, 2014 at 22:37

This has been covered here quite well, but if you REALLY need even better performance than anything listed here, you can use this approach that uses strtok.

$Names_Keys = [];
$Name = strtok[file_get_contents[$file], "\n"];
while [$Name !== false] {
    $Names_Keys[$Name] = 0;
    $Name = strtok["\n"];
}

Note, this assumes your file is saved with \n as the newline character [you can update that as need be], and it also stores the words/names/lines as the array keys instead of the values, so that you can use it as a lookup table, allowing the use of isset [much, much faster], instead of in_array.

answered Feb 21, 2018 at 20:59

Brian LeishmanBrian Leishman

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