I'm trying to xor 2 binaries using python like this but my output is not in binary any help?
a = "11011111101100110110011001011101000"
b = "11001011101100111000011100001100001"
y = int[a] ^ int[b]
print y
karthikr
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asked Oct 16, 2013 at 21:19
1
a="11011111101100110110011001011101000"
b="11001011101100111000011100001100001"
y=int[a,2] ^ int[b,2]
print['{0:b}'.format[y]]
answered Oct 16, 2013 at 21:20
RobᵩRobᵩ
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4
To get the Xor'd binary to the same length, as per the OP's request, do the following:
a = "11011111101100110110011001011101000"
b = "11001011101100111000011100001100001"
y = int[a, 2]^int[b,2]
print bin[y][2:].zfill[len[a]]
[output: 00010100000000001110000101010001001]
Convert the binary strings to an integer base 2, then XOR, then bin[] and then skip the first two characters, 0b, hence the bin[y0][2:].
After that, just zfill to the length - len[a], for this case.
Cheers
Matan Itzhak
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answered Mar 19, 2017 at 16:21
BigHBigH
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Since you are trying to carryout XOR on the same length binaries, the following should work just fine:
c=[str[int[a[i]]^int[b[i]]] for i in range[len[a]]]
c=''.join[c]
You can avoid the formatting altogether.
answered Nov 27, 2020 at 17:26
Since you are starting with strings and want a string result, you may find this interesting but it only works if they are the same length.
y = ''.join['0' if i == j else '1' for i, j in zip[a,b]]
If they might be different lengths you can do:
y = ''.join['0' if i == j else '1' for i, j in zip[a[::-1],b[::-1]][::-1]]
y = a[len[y]:] + b[len[y]:] + y
answered Oct 16, 2013 at 23:29
dansalmodansalmo
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Given two binary strings A and B of equal lengths, the task is to print a string which is the XOR of Binary
Strings A and B.
Examples:
Input: A = “0001”, B = “0010”
Output: 0011
Input: A = “1010”, B = “0101”
Output: 1111
Approach: The idea is to iterate over both the string character by character and if the character mismatched then add “1” as the character in the answer
string otherwise add “0” to the answer string to generate the XOR string.
Below is the implementation of the above approach:
C++
#include
using namespace std;
string xoring[string a, string b, int n]{
string ans = "";
for [int i = 0; i < n; i++]
{
if [a[i] == b[i]]
ans += "0";
else
ans += "1";
}
return ans;
}
int main[]
{
string a = "1010";
string b = "1101";
int n = a.length[];
string c = xoring[a, b, n];
cout