Java Collection How to - Compare elements in list and remove if some properties are the same
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Question
We would like to know how to compare elements in list and remove if some properties are the same.
Answer
import java.util.ArrayList; import java.util.HashSet; import java.util.List; import java.util.Set; //w ww.ja va 2 s. c o m class Employee { private String name; private String address; private String phone; public Employee[] { super[]; } public Employee[String name, String address, String phone] { super[]; this.name = name; this.address = address; this.phone = phone; } public String getName[] { return name; } public void setName[String name] { this.name = name; } public String getAddress[] { return address; } public void setAddress[String address] { this.address = address; } public String getPhone[] { return phone; } public void setPhone[String phone] { this.phone = phone; } @Override public int hashCode[] { final int prime = 31; int result = 1; result = prime * result + [[address == null] ? 0 : address.hashCode[]]; result = prime * result + [[name == null] ? 0 : name.hashCode[]]; result = prime * result + [[phone == null] ? 0 : phone.hashCode[]]; return result; } @Override public boolean equals[Object obj] { if [this == obj] return true; if [obj == null] return false; if [getClass[] != obj.getClass[]] return false; Employee other = [Employee] obj; if [address == null] { if [other.address != null] return false; } else if [!address.equals[other.address]] return false; if [name == null] { if [other.name != null] return false; } else if [!name.equals[other.name]] return false; if [phone == null] { if [other.phone != null] return false; } else if [!phone.equals[other.phone]] return false; return true; } @Override public String toString[] { return "Employee [name=" + name + ", address=" + address + ", phone=" + phone + "]"; } } public class Main { public static void main[String[] args] { Set empSet = new HashSet[populateList[]]; for [Employee employee : empSet] { System.out.println[employee]; } } public static List populateList[] { List lsts = new ArrayList[]; lsts.add[new Employee["A", "B", "123456"]]; lsts.add[new Employee["C", "E", "123685"]]; lsts.add[new Employee["D", "F", "1257456"]]; lsts.add[new Employee["D", "F", "196356"]]; lsts.add[new Employee["A", "B", "123456"]]; lsts.add[new Employee["A", "B", "123456"]]; lsts.add[new Employee["A", "B", "123456"]]; return lsts; } }The code above generates the following result.
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