Which method returns the smallest integer greater than or equal to a number?

TIL: For certain reasons 🥁 I did a coding challenge on Codility for once and now I want to share my approaches with you.

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• Table of contents
• Approach 1: For-Loop
• Approach 2: Map-Function
• Approach 3: Set
• Which method returns the smallest integer greater than or equal to a number?
• Which is the smallest integer greater than the negative integer?
• Which of the following number method returns the smallest integer that is greater than or equal to the arguments in Java?
• What is the smallest positive integer n for which?

Table of contents

Task

Write a function:

function solution[A] {
    let x = 1

    A.filter[x => x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  num >= 1].sort[[a, b] => a - b];
  let x = 1;

  for[let i = 0; i = 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x  x >= 1]
     .sort[[a, b] => a - b]
     .map[[val, i, arr] => {
        if[x