Warning: timeit results may vary due to differences in hardware or version of Python.
Below is a script which compares a number of implementations:
- ambi_sieve_plain,
- rwh_primes,
- rwh_primes1,
- rwh_primes2,
- sieveOfAtkin,
- sieveOfEratosthenes,
- sundaram3,
- sieve_wheel_30,
- ambi_sieve (requires numpy)
- primesfrom3to (requires numpy)
- primesfrom2to (requires numpy)
Many thanks to stephan for bringing sieve_wheel_30 to my attention. Credit goes to Robert William Hanks for primesfrom2to, primesfrom3to, rwh_primes, rwh_primes1, and rwh_primes2.
Of the plain Python methods tested, with psyco, for n=1000000, rwh_primes1 was the fastest tested.
+---------------------+-------+ | Method | ms | +---------------------+-------+ | rwh_primes1 | 43.0 | | sieveOfAtkin | 46.4 | | rwh_primes | 57.4 | | sieve_wheel_30 | 63.0 | | rwh_primes2 | 67.8 | | sieveOfEratosthenes | 147.0 | | ambi_sieve_plain | 152.0 | | sundaram3 | 194.0 | +---------------------+-------+
Of the plain Python methods tested, without psyco, for n=1000000, rwh_primes2 was the fastest.
+---------------------+-------+ | Method | ms | +---------------------+-------+ | rwh_primes2 | 68.1 | | rwh_primes1 | 93.7 | | rwh_primes | 94.6 | | sieve_wheel_30 | 97.4 | | sieveOfEratosthenes | 178.0 | | ambi_sieve_plain | 286.0 | | sieveOfAtkin | 314.0 | | sundaram3 | 416.0 | +---------------------+-------+
Of all the methods tested, allowing numpy, for n=1000000, primesfrom2to was the fastest tested.
+---------------------+-------+ | Method | ms | +---------------------+-------+ | primesfrom2to | 15.9 | | primesfrom3to | 18.4 | | ambi_sieve | 29.3 | +---------------------+-------+
Timings were measured using the command:
python -mtimeit -s"import primes" "primes.{method}(1000000)"
with {method} replaced by each of the method names.
primes.py:
#!/usr/bin/env python import psyco; psyco.full() from math import sqrt, ceil import numpy as np def rwh_primes(n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/3035188#3035188 """ Returns a list of primes < n """ sieve = [True] * n for i in xrange(3,int(n**0.5)+1,2): if sieve[i]: sieve[i*i::2*i]=[False]*((n-i*i-1)/(2*i)+1) return [2] + [i for i in xrange(3,n,2) if sieve[i]] def rwh_primes1(n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/3035188#3035188 """ Returns a list of primes < n """ sieve = [True] * (n/2) for i in xrange(3,int(n**0.5)+1,2): if sieve[i/2]: sieve[i*i/2::i] = [False] * ((n-i*i-1)/(2*i)+1) return [2] + [2*i+1 for i in xrange(1,n/2) if sieve[i]] def rwh_primes2(n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/3035188#3035188 """ Input n>=6, Returns a list of primes, 2 <= p < n """ correction = (n%6>1) n = {0:n,1:n-1,2:n+4,3:n+3,4:n+2,5:n+1}[n%6] sieve = [True] * (n/3) sieve[0] = False for i in xrange(int(n**0.5)/3+1): if sieve[i]: k=3*i+1|1 sieve[ ((k*k)/3) ::2*k]=[False]*((n/6-(k*k)/6-1)/k+1) sieve[(k*k+4*k-2*k*(i&1))/3::2*k]=[False]*((n/6-(k*k+4*k-2*k*(i&1))/6-1)/k+1) return [2,3] + [3*i+1|1 for i in xrange(1,n/3-correction) if sieve[i]] def sieve_wheel_30(N): # http://zerovolt.com/?p=88 ''' Returns a list of primes <= N using wheel criterion 2*3*5 = 30 Copyright 2009 by zerovolt.com This code is free for non-commercial purposes, in which case you can just leave this comment as a credit for my work. If you need this code for commercial purposes, please contact me by sending an email to: info [at] zerovolt [dot] com.''' __smallp = ( 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997) wheel = (2, 3, 5) const = 30 if N < 2: return [] if N <= const: pos = 0 while __smallp[pos] <= N: pos += 1 return list(__smallp[:pos]) # make the offsets list offsets = (7, 11, 13, 17, 19, 23, 29, 1) # prepare the list p = [2, 3, 5] dim = 2 + N // const tk1 = [True] * dim tk7 = [True] * dim tk11 = [True] * dim tk13 = [True] * dim tk17 = [True] * dim tk19 = [True] * dim tk23 = [True] * dim tk29 = [True] * dim tk1[0] = False # help dictionary d # d[a , b] = c ==> if I want to find the smallest useful multiple of (30*pos)+a # on tkc, then I need the index given by the product of [(30*pos)+a][(30*pos)+b] # in general. If b < a, I need [(30*pos)+a][(30*(pos+1))+b] d = {} for x in offsets: for y in offsets: res = (x*y) % const if res in offsets: d[(x, res)] = y # another help dictionary: gives tkx calling tmptk[x] tmptk = {1:tk1, 7:tk7, 11:tk11, 13:tk13, 17:tk17, 19:tk19, 23:tk23, 29:tk29} pos, prime, lastadded, stop = 0, 0, 0, int(ceil(sqrt(N))) # inner functions definition def del_mult(tk, start, step): for k in xrange(start, len(tk), step): tk[k] = False # end of inner functions definition cpos = const * pos while prime < stop: # 30k + 7 if tk7[pos]: prime = cpos + 7 p.append(prime) lastadded = 7 for off in offsets: tmp = d[(7, off)] start = (pos + prime) if off == 7 else (prime * (const * (pos + 1 if tmp < 7 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 11 if tk11[pos]: prime = cpos + 11 p.append(prime) lastadded = 11 for off in offsets: tmp = d[(11, off)] start = (pos + prime) if off == 11 else (prime * (const * (pos + 1 if tmp < 11 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 13 if tk13[pos]: prime = cpos + 13 p.append(prime) lastadded = 13 for off in offsets: tmp = d[(13, off)] start = (pos + prime) if off == 13 else (prime * (const * (pos + 1 if tmp < 13 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 17 if tk17[pos]: prime = cpos + 17 p.append(prime) lastadded = 17 for off in offsets: tmp = d[(17, off)] start = (pos + prime) if off == 17 else (prime * (const * (pos + 1 if tmp < 17 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 19 if tk19[pos]: prime = cpos + 19 p.append(prime) lastadded = 19 for off in offsets: tmp = d[(19, off)] start = (pos + prime) if off == 19 else (prime * (const * (pos + 1 if tmp < 19 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 23 if tk23[pos]: prime = cpos + 23 p.append(prime) lastadded = 23 for off in offsets: tmp = d[(23, off)] start = (pos + prime) if off == 23 else (prime * (const * (pos + 1 if tmp < 23 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # 30k + 29 if tk29[pos]: prime = cpos + 29 p.append(prime) lastadded = 29 for off in offsets: tmp = d[(29, off)] start = (pos + prime) if off == 29 else (prime * (const * (pos + 1 if tmp < 29 else 0) + tmp) )//const del_mult(tmptk[off], start, prime) # now we go back to top tk1, so we need to increase pos by 1 pos += 1 cpos = const * pos # 30k + 1 if tk1[pos]: prime = cpos + 1 p.append(prime) lastadded = 1 for off in offsets: tmp = d[(1, off)] start = (pos + prime) if off == 1 else (prime * (const * pos + tmp) )//const del_mult(tmptk[off], start, prime) # time to add remaining primes # if lastadded == 1, remove last element and start adding them from tk1 # this way we don't need an "if" within the last while if lastadded == 1: p.pop() # now complete for every other possible prime while pos < len(tk1): cpos = const * pos if tk1[pos]: p.append(cpos + 1) if tk7[pos]: p.append(cpos + 7) if tk11[pos]: p.append(cpos + 11) if tk13[pos]: p.append(cpos + 13) if tk17[pos]: p.append(cpos + 17) if tk19[pos]: p.append(cpos + 19) if tk23[pos]: p.append(cpos + 23) if tk29[pos]: p.append(cpos + 29) pos += 1 # remove exceeding if present pos = len(p) - 1 while p[pos] > N: pos -= 1 if pos < len(p) - 1: del p[pos+1:] # return p list return p def sieveOfEratosthenes(n): """sieveOfEratosthenes(n): return the list of the primes < n.""" # Code from: <>, Nov 30 2006 # http://groups.google.com/group/comp.lang.python/msg/f1f10ced88c68c2d if n <= 2: return [] sieve = range(3, n, 2) top = len(sieve) for si in sieve: if si: bottom = (si*si - 3) // 2 if bottom >= top: break sieve[bottom::si] = [0] * -((bottom - top) // si) return [2] + [el for el in sieve if el] def sieveOfAtkin(end): """sieveOfAtkin(end): return a list of all the prime numbers <>, improved # Code: https://web.archive.org/web/20080324064651/http://krenzel.info/?p=83 # Info: http://en.wikipedia.org/wiki/Sieve_of_Atkin assert end > 0 lng = ((end-1) // 2) sieve = [False] * (lng + 1) x_max, x2, xd = int(sqrt((end-1)/4.0)), 0, 4 for xd in xrange(4, 8*x_max + 2, 8): x2 += xd y_max = int(sqrt(end-x2)) n, n_diff = x2 + y_max*y_max, (y_max << 1) - 1 if not (n & 1): n -= n_diff n_diff -= 2 for d in xrange((n_diff - 1) << 1, -1, -8): m = n % 12 if m == 1 or m == 5: m = n >> 1 sieve[m] = not sieve[m] n -= d x_max, x2, xd = int(sqrt((end-1) / 3.0)), 0, 3 for xd in xrange(3, 6 * x_max + 2, 6): x2 += xd y_max = int(sqrt(end-x2)) n, n_diff = x2 + y_max*y_max, (y_max << 1) - 1 if not(n & 1): n -= n_diff n_diff -= 2 for d in xrange((n_diff - 1) << 1, -1, -8): if n % 12 == 7: m = n >> 1 sieve[m] = not sieve[m] n -= d x_max, y_min, x2, xd = int((2 + sqrt(4-8*(1-end)))/4), -1, 0, 3 for x in xrange(1, x_max + 1): x2 += xd xd += 6 if x2 >= end: y_min = (((int(ceil(sqrt(x2 - end))) - 1) << 1) - 2) << 1 n, n_diff = ((x*x + x) << 1) - 1, (((x-1) << 1) - 2) << 1 for d in xrange(n_diff, y_min, -8): if n % 12 == 11: m = n >> 1 sieve[m] = not sieve[m] n += d primes = [2, 3] if end <= 3: return primes[:max(0,end-2)] for n in xrange(5 >> 1, (int(sqrt(end))+1) >> 1): if sieve[n]: primes.append((n << 1) + 1) aux = (n << 1) + 1 aux *= aux for k in xrange(aux, end, 2 * aux): sieve[k >> 1] = False s = int(sqrt(end)) + 1 if s % 2 == 0: s += 1 primes.extend([i for i in xrange(s, end, 2) if sieve[i >> 1]]) return primes def ambi_sieve_plain(n): s = range(3, n, 2) for m in xrange(3, int(n**0.5)+1, 2): if s[(m-3)/2]: for t in xrange((m*m-3)/2,(n>>1)-1,m): s[t]=0 return [2]+[t for t in s if t>0] def sundaram3(max_n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/2073279#2073279 numbers = range(3, max_n+1, 2) half = (max_n)//2 initial = 4 for step in xrange(3, max_n+1, 2): for i in xrange(initial, half, step): numbers[i-1] = 0 initial += 2*(step+1) if initial > half: return [2] + filter(None, numbers) ################################################################################ # Using Numpy: def ambi_sieve(n): # http://tommih.blogspot.com/2009/04/fast-prime-number-generator.html s = np.arange(3, n, 2) for m in xrange(3, int(n ** 0.5)+1, 2): if s[(m-3)/2]: s[(m*m-3)/2::m]=0 return np.r_[2, s[s>0]] def primesfrom3to(n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/3035188#3035188 """ Returns a array of primes, p < n """ assert n>=2 sieve = np.ones(n/2, dtype=np.bool) for i in xrange(3,int(n**0.5)+1,2): if sieve[i/2]: sieve[i*i/2::i] = False return np.r_[2, 2*np.nonzero(sieve)[0][1::]+1] def primesfrom2to(n): # https://stackoverflow.com/questions/2068372/fastest-way-to-list-all-primes-below-n-in-python/3035188#3035188 """ Input n>=6, Returns a array of primes, 2 <= p < n """ sieve = np.ones(n/3 + (n%6==2), dtype=np.bool) sieve[0] = False for i in xrange(int(n**0.5)/3+1): if sieve[i]: k=3*i+1|1 sieve[ ((k*k)/3) ::2*k] = False sieve[(k*k+4*k-2*k*(i&1))/3::2*k] = False return np.r_[2,3,((3*np.nonzero(sieve)[0]+1)|1)] if __name__=='__main__': import itertools import sys def test(f1,f2,num): print('Testing {f1} and {f2} return same results'.format( f1=f1.func_name, f2=f2.func_name)) if not all([a==b for a,b in itertools.izip_longest(f1(num),f2(num))]): sys.exit("Error: %s(%s) != %s(%s)"%(f1.func_name,num,f2.func_name,num)) n=1000000 test(sieveOfAtkin,sieveOfEratosthenes,n) test(sieveOfAtkin,ambi_sieve,n) test(sieveOfAtkin,ambi_sieve_plain,n) test(sieveOfAtkin,sundaram3,n) test(sieveOfAtkin,sieve_wheel_30,n) test(sieveOfAtkin,primesfrom3to,n) test(sieveOfAtkin,primesfrom2to,n) test(sieveOfAtkin,rwh_primes,n) test(sieveOfAtkin,rwh_primes1,n) test(sieveOfAtkin,rwh_primes2,n)
Running the script tests that all implementations give the same result.
What is the fastest way to get prime numbers in Python?
We check if num is exactly divisible by any number from 2 to num - 1 . If we find a factor in that range, the number is not prime, so we set flag to True and break out of the loop. Outside the loop, we check if flag is True or False . If it is True , num is not a prime number.
What is the fastest way to find a prime number?
Take a number, say, 26577. The unit digit of this number is not 0, 2, 4, 6 or 8. Now, take the sum of digits which will be: 2 + 6 + 5 + 7 + 7 = 27. Since 27 is divisible by 3, 26577 is not a prime number.
How do you check if a number is prime quickly Python?
Method 1: Using isprime() to check if a number is prime or not in python.
1.1 Code. def isprime(num): for n in range ( 2 , int (num * * 0.5 ) + 1 ): if num % n = = 0 : ... .
1.2 Code. def isprime(num): if num = = 2 or num = = 3 : ... .
1.3 Code. def isprime(num): if num = = 2 or num = = 3 : ... .
1.4 Code. def isprime(num): if num> 1 :.
Is prime Fast Python?
Function isPrime2 is faster in returning True for prime numbers. But if a number is big and it is not prime, it takes too long to return a value. First function works better with that.