Can i shuffle dictionary in python?

Well I think that you can also do it simpler, without lambdas etc.:

from random import shuffle
from collections import OrderedDict 
a = {num-97:chr(num) for num in range(97, 107)}
# a = {0: 'a', 1: 'b', 2: 'c', 3: 'd', 4: 'e', 5: 'f', 6: 'g', 7: 'h', 8: 'i', 9: 'j'}
b = list(a.items())
shuffle(b)
a = OrderedDict(b) #Or just stay with b
# a = OrderedDict([(1, 'b'), (6, 'g'), (4, 'e'), (3, 'd'), (5, 'f'), (8, 'i'), (2, 'c'), (7, 'h'), (9, 'j'), (0, 'a')])
# b = [(1, 'b'), (6, 'g'), (4, 'e'), (3, 'd'), (5, 'f'), (8, 'i'), (2, 'c'), (7, 'h'), (9, 'j'), (0, 'a')]

I think that using shuffle makes the code clearer then using sorted with random key.

For shuffling keys only it would make something like:

keys = list(a.keys())
shuffle(keys)
OrderedDict(zip(keys, a.values()))
# OrderedDict([(3, 'a'), (1, 'b'), (9, 'c'), (4, 'd'), (6, 'e'), (8, 'f'), (0, 'g'), (2, 'h'), (5, 'i'), (7, 'j')])

Given a dictionary, the task is to write a python program to shuffle its values to different keys.

Examples:

Input: test_dict = {“gfg” : 1, “is” : 7, “best” : 8, “for” : 3, “geeks” : 9}

Output : {“gfg” : 9, “is” : 8, “best” : 7, “for” : 3, “geeks” : 1}

Explanation : Keys are at same position but values are shuffled.

Input : test_dict = {“gfg” : 7, “is” : 1, “best” : 8, “for” : 3, “geeks” : 9}

Output : {“gfg” : 9, “is” : 8, “best” : 7, “for” : 3, “geeks” : 1}

Explanation : Keys are at same position but values are shuffled.

Method #1 : Using shuffle() + zip() + dict()

In this, we perform the task of shuffling elements using shuffle(), and zip() is used to map the shuffled values to keys. In the end, dict() is used to convert the result to a dictionary.

Python3

import random

test_dict = {"gfg": 1, "is": 7, "best": 8, 

             "for": 3, "geeks": 9}

print("The original dictionary is : " + str(test_dict))

temp = list(test_dict.values())

random.shuffle(temp)

res = dict(zip(test_dict, temp))

print("The shuffled dictionary : " + str(res))

Output:

The original dictionary is : {‘gfg’: 1, ‘is’: 7, ‘best’: 8, ‘for’: 3, ‘geeks’: 9}

The shuffled dictionary : {‘gfg’: 1, ‘is’: 7, ‘best’: 3, ‘for’: 9, ‘geeks’: 8}

Method #2 : Using sample() + zip()

In this, the task of shuffling values is done using sample() of random library.

Python3

from random import sample

test_dict = {"gfg": 1, "is": 7, "best": 8, 

             "for": 3, "geeks": 9}

print("The original dictionary is : " + str(test_dict))

res = dict(zip(test_dict, sample(list(test_dict.values()), 

                                 len(test_dict))))

print("The shuffled dictionary : " + str(res))

Output:

The original dictionary is : {‘gfg’: 1, ‘is’: 7, ‘best’: 8, ‘for’: 3, ‘geeks’: 9}

The shuffled dictionary : {‘gfg’: 8, ‘is’: 9, ‘best’: 1, ‘for’: 3, ‘geeks’: 7}

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