How many words with or without means each of two vowels and three consonants honesty?

My solution:

In the word INVOLUTE, there are $4$ vowels, namely, I,O,E,U and $4$ consonants, namely, N, V, L and T.

The number of ways of selecting $3$ vowels out of $4 = C(4,3) = 4$. The number of ways of selecting $2$ consonants out of $4 = C(4,2) = 6$. Therefore, the number of combinations of $3$ vowels and $2$ consonants is $4+6=10$.

Now, each of these $10$ combinations has $5$ letters which can be arranged among themselves in $5!$ ways. Therefore, the required number of different words is $10\times5! = 1200$.

But the answer is $2880$.

What am I doing wrong? Please explain.

The word games Words With Friends, 4pics1Word, Word Chums, and Jumble which is by far one of the most successful of the word games. Jumble was created in 1954 - below, you will find the most unscrambled letters for each descramble word game that others have solved or decoded to make the word honesty.

Is honesty a scrabble word or can you use honesty in Words With Friends? The probability of getting this word in scrabble is 1 out of every 289489 games and in Words With Friends it's 1 out of every 145902 games. This 7 letter 13 point scrabble word can be rearranged 5,040 ways. What other words can be made with the letters e, h, n, o, s, t, and y? There's 1 with 9 letters or less with the letters e, h, n, o, s, t, and y. Here is a list of 1 to try to get you more points.

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Indus question we have to choose two hours and consonant from the letters of word daughter and we have to find it in how many words we can make by using two hours and 3 consonants so in word consonant we have one De 1A 1u 1GB 1h 1t 1e and one hour so we have all different letter this 8 letter how many hours this is mobile Evil you is evil

and is over and how many consonants here is consonant G consonant letters consonant please consonant and vowel consonant 35 sothi bubble message to bhabhi choose karne ke bich kitne Honge 3 C2 first counselling dates message free concert use karne ke liye kitne Honge 52 suit total number of formations Kitni Hogi 3 consonant this is 35 C3 because you to choose three consonant total number of formation kitne hue total is equal to

3C 225 C3 it is equal to 3 into 5 into 4 upon 2 is equal to 3 into 10 30 30 number of possible combinations of two vowels and 3 consonants and we know he is combination memory five different letter use karen to 15 different letters were arranged kaise kar sakte ho sakta Railway se total possible words on total possible word meaning Phool aur meaningless total possible words equal to 5 factorial

in 235 factorial is equal to 120 into 32223 36 total number of vedar 3600

Misc 1 - Chapter 7 Class 11 Permutations and Combinations (Term 2)

Last updated at Jan. 13, 2022 by

How many words with or without means each of two vowels and three consonants honesty?

How many words with or without means each of two vowels and three consonants honesty?

How many words with or without means each of two vowels and three consonants honesty?

How many words with or without means each of two vowels and three consonants honesty?

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Transcript

Misc 1 How many words, with or without meaning, each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER? Number ways of selecting 2 vowels & 3 consonants = 3C2 × 5C3 = 3!/2!(3 − 2)! × 5!/3!(5 − 3)! = 3!/2!1! × 5!/3!2! = 30 Now, Each of these 5 letters can be arranged in 5 ways Number of arrangements = 5P5 = 5!/(5 − 5)! = 5!/0! = 5! = 5 × 4 × 3 × 2 × 1 = 120 Thus, Total number of words = Number of ways of selecting × Number of arrangements = 30 × 120 = 3600

How many words with or without means each of two vowels and three consonants?

Therefore, 30 words can be formed from the letters of the word DAUGHTER each containing 2 vowels and 3 consonants.

How many words with or without meaning each of 2 vowels and 3 consonants can be formed from the letters of the word shoulder?

Solution 1 Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among themselves in 5! ways.

How many words contain two vowels and three consonants?

So, total number of words = 5C2× 17C3×5! =816000.

How many words may be formed with 3 consonants and 2 vowels so that no two consonants remain together?

Number of groups, each having 3 consonants and 2 vowels = 210.