How to extract last digit of a number in python

Is there a way to get the last digit of a number. I am trying to find variables that end with "1" like 1,11,21,31,41,etc..

If I use a text variable I can simply put

print number[:-1] 

but it works for variables with text(like "hello) but not with numbers. With numbers I get this error:

TypeError: 'int' object is not subscriptable

I am trying to see if there's a better way to deal with numbers this way. I know a solution is to convert to a string and then do the above command but I'm trying to see if there's another way I have missed.

Thanks so much in advance...

asked Mar 10, 2011 at 2:36

Remainder when dividing by 10, as in

numericVariable % 10

This only works for positive numbers. -12%10 yields 8

answered Mar 10, 2011 at 2:36

Jim GarrisonJim Garrison

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0

Use the modulus operator with 10:

num = 11
if num % 10 == 1:
    print 'Whee!'

This gives the remainder when dividing by 10, which will always be the last digit (when the number is positive).

answered Mar 10, 2011 at 2:37

CameronCameron

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2

So you want to access the digits in a integer like elements in a list; easiest way I can think of is:

n = 56789
lastdigit = int(repr(n)[-1])
# >  9

Convert n into a string, accessing last element then use int constructor to convert back into integer.

For a Floating point number:

n = 179.123
fstr = repr(n)
signif_digits, fract_digits = fstr.split('.')
# >  ['179', '123']
signif_lastdigit = int(signif_digits[-1])
# >  9

answered Oct 17, 2011 at 5:07

Zv_oDDZv_oDD

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1

I can't add a comment yet, but I wanted to iterate and expand on what Jim Garrison said

Remainder when dividing by 10, as in numericVariable % 10

This only works for positive numbers. -12%10 yields 8

While modulus (%) is working as intended, throw on an absolute value to use the modulus in this situation.

abs(numericVariable) % 10

answered Feb 21, 2017 at 21:19

Micah PearceMicah Pearce

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Lostsoul, this should work:

    number = int(10)
#The variable number can also be a float or double, and I think it should still work.
lastDigit = int(repr(number)[-1])
#This gives the last digit of the variable "number." 
if lastDigit == 1 : 
    print("The number ends in 1!")

Instead of the print statement at the end, you can add code to do what you need to with numbers ending in 1.

Hope it helped!

answered Feb 3, 2019 at 3:37

Convert to string first:

oldint = 10101
newint = int(str(oldint)[-1:]) 

answered Dec 15, 2019 at 3:05

JayJay

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The simplest and most efficient way is to use the reminder :

last_digit = orginal_number % 10

answered Aug 14, 2020 at 17:37

1

This is a simple yet effective way to do it

if number < 0:
       remainder = number % -10
else:
       remainder = number % 10

answered Jun 28 at 10:29

1

By using iteration and the in built function of 'digit' the number is treated as binary and so it goes from backwards to forwards. Here is an example of a bit of code for you.

for digit in binary:
    denary= denary*2 + int(digit)

answered Nov 5, 2017 at 15:02

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