What is the probability that you obtain a sum of 7 or a sum of 11 on the first roll?

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Solution

The correct option is D. 16Given,Sample space for rolling a pair of dice = S { (1,1) , (1,2) , (1,3) , (1,4), (1,5), (1,6) , (adsbygoogle = window.adsbygoogle || []).push({}); (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }⇒ Total number of outcomes = 36From the sample space, (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1) gives sum of 7.⇒ Number of favourable outcomes = 6 (adsbygoogle = window.adsbygoogle || []).push({}); Probability of an event, P(E) = number of favourable outcomestotal number of outcomesP ( getting sum 7) =636=16 Therefore, the probability of getting a sum of 7 on rolling a pair of dice is 16.

What is the probability of a sum of 7 or 11?

So, P(sum of 7 or 11) = 2/9.

What is the probability of rolling a 7 or 11?

Let us try to calculate the probability of winning. We can use the probabilities we calculated on the previous page. The probability of winning on the first roll is the probability of rolling 7 or 11, which is 1/6 plus 1/18, which equals to 2/9.

How many outcomes give the sum of 7 or the sum of 11?

As shown above, there are 8 possible outcomes where the sum is 7 or 11.

How many ways are there to roll a sum of 7 or 11 on two dice B How many ways are there to roll doubles or a sum divisible by three on two dice?

1 Answer. There are six ways we can have 7 and two ways, we can have 11 on two dices.