Get unique values from 2d array javascript

Question

If you can use lodash, this is good solution (note that based on your platform, the "require" keyword can differ, this is how to use it in Node.js):

var _ = require('lodash');
var objects = [['a', 'b', 'c'],['a'],['b', 'a', 'c']];
objects.forEach(innerArr => {
  innerArr.sort();
});
console.log(_.uniqWith(objects, _.isEqual));

This would be output

[ [ 'a', 'b', 'c' ], [ 'a' ] ]

If order of elements in array matter to you, i.e. this array [ 'a', 'b', 'c' ] is considered different than this one ['b', 'a', 'c'], all you need is to delete the "sort" part :

var _ = require('lodash');
var objects = [['a', 'b', 'c'],['a'],['b', 'a', 'c'], ['a','b','c']];
console.log(_.uniqWith(objects, _.isEqual));

This would be output :

[ [ 'a', 'b', 'c' ], [ 'a' ], [ 'b', 'a', 'c' ] ]

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Javascript Source Code

The Javascript source code to do "Javascript Array get distinct values in a 2D array" is

var items = [['al','bv','sd'],
             ['al','cc','ab'],
             ['cv','vv','sw'],
             ['al','bv','sd']
            ];//   w  w  w  .  d   e  mo    2 s  .  c  o   m
function arrays_equal(a,b) { return !!a && !!b && !(aArray.prototype.unique = function() {
    var a = [];
    for (var i = 0, l = this.length; ifor (var j = i + 1; j < l; j++) if (arrays_equal(this[i], this[j])) j = ++i;
        a.push(this[i]);
    }
    return a;
};
var ret = items.unique();
console.log(ret);

//solution 2

  var items = [['al','bv','sd'],
             ['al','cc','ab'],
             ['cv','vv','sw'],
             ['al','bv','sd']
            ];
for (var i=0; ilength; i++) {
    var listI = items[i];
    loopJ: for (var j=0; jlength; j++) {
        var listJ = items[j];
        if (listI === listJ) continue; //Ignore itself
        for (var k=listJ.length; k>=0; k--) {
            if (listJ[k] !== listI[k]) continue loopJ;
        }
        // At this point, their values are equal.
        items.splice(j, 1);
    }
}
document.body.innerHTML = items.join('
');

<html>
<head>
  <meta name="viewport" content="width=device-width, initial-scale=1">
<!--  w  w w  .   d e  m    o  2  s.    c o   m-->
<body>
    <script type='text/javascript'>
var items = [['al','bv','sd'],
             ['al','cc','ab'],
             ['cv','vv','sw'],
             ['al','bv','sd']
            ];
function arrays_equal(a,b) { return !!a && !!b && !(a<b || b<a); }
Array.prototype.unique = function() {
    var a = [];
    for (var i = 0, l = this.length; i<l; i++) {
        for (var j = i + 1; j < l; j++) if (arrays_equal(this[i], this[j])) j = ++i;
        a.push(this[i]);
    }
    return a;
};
var ret = items.unique();
console.log(ret);

//solution 2

  var items = [['al','bv','sd'],
             ['al','cc','ab'],
             ['cv','vv','sw'],
             ['al','bv','sd']
            ];
for (var i=0; i<items.length; i++) {
    var listI = items[i];
    loopJ: for (var j=0; j<items.length; j++) {
        var listJ = items[j];
        if (listI === listJ) continue; //Ignore itself
        for (var k=listJ.length; k>=0; k--) {
            if (listJ[k] !== listI[k]) continue loopJ;
        }
        // At this point, their values are equal.
        items.splice(j, 1);
    }
}
document.body.innerHTML = items.join('
');

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Javascript Source Code

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