How many 5 digit numbers are there whose digits are in increasing order?


How many 5 digit numbers are there whose digits are in increasing order?

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How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  20 Dec 2017, 01:34

How many 5 digit numbers are there whose digits are in increasing order?

How many 5 digit numbers are there whose digits are in increasing order?

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Question Stats:

How many 5 digit numbers are there whose digits are in increasing order?
39% (02:32) correct
How many 5 digit numbers are there whose digits are in increasing order?
61% (02:13) wrong
How many 5 digit numbers are there whose digits are in increasing order?
based on 298 sessions

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GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

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Math Expert

Joined: 02 Aug 2009

Posts: 10653

How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  01 Jan 2018, 06:34

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Hi..

an easier, short and logical way..

choose 4 out of 10... there can be ONLY 1 way the 4 can be arranged in ascending order, so selection is what we are looking for and NOT arrangements..
\(10C4 = \frac{10!}{6!4!} = \frac{10*9*8*7}{4*3*2} = 210\)

BUT it contains numbers with 0 in thousands digit making these 3-digit numbers
so \(9C3= \frac{9!}{6!3!} = 84\)

\(ans = 210-84=126\)

D
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  18 Nov 2021, 03:17

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Official Solution:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. \(6\)
B. \(7\)
C. \(84\)
D. \(126\)
E. \(210\)

First of all, notice that 0 cannot be a digit of such numbers: 0 cannot be the first digit, since in this case a number will no longer be a four-digit number and become a three-digit number; and also it cannot be any other digit, since the digits must be in ascending order.

So, such numbers can have only 4 different digits out of 9 (all digits but 0). The number of groups of 4 different digits out of 9 is \(9C4=126\) and since only one arrangement of any of such groups will be in ascending order then 126 is the final answer. For example, if the group of 4 we choose is {3, 5, 7, 1}, the only way to arrange this group of digits in ascending order is 1357.

Answer: D
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  01 Jan 2018, 06:44

chetan2u wrote:

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Hi..

an easier, short and logical way..

choose 4 out of 10... there can be ONLY 1 way the 4 can be arranged in ascending order, so selection is what we are looking for and NOT arrangements..
\(10C4 = \frac{10!}{6!4!} = \frac{10*9*8*7}{4*3*2} = 210\)

BUT it contains numbers with 0 in thousands digit making these 3-digit numbers
so \(9C3= \frac{9!}{6!3!} = 84\)

\(ans = 210-84=126\)

D

Great explanation chetan2u

How many 5 digit numbers are there whose digits are in increasing order?

we can reduce 1 step here because \(0\) cannot be part of any number with ascending digits so we simply need to select \(4\) digits out of \(9\) digits

Hence \(9_C_4=\frac{9!}{4!5!}=126\)

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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  20 Dec 2017, 05:23

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

First Digit - A
Second Digit - B
Third Digit - C
Fourth Digit - D

A can be 1-6
B can be 2-7
C can be 3-8
D can be 4-9
A=1; B = 2; C = 3 ; D = 6 options
A=1; B = 2; C = 4; D = 5 options
A = 1; B=2; C = 5; D = 4 options
A = 1; B=2; C = 6; D = 3 options
A = 1; B=2; C = 7; D = 2 options
A = 1; B=2; C = 8; D = 1 options
So When A =1 and B=2 then we have 21 options
WHen A = 1 and B=3 then we have 15 options
When A =1 and B=4 then we have 10 options
When A = 1 and B=5 then we have 6 options
When A = 1 and B=6 then we have 3 options
When A = 1 and B=7 then we have 1 option
So When A =1 we have 56 options
WHen A = 2 we have 35 options
When A = 3 we have 20 options
When A = 4 we have 10 options
When A = 5 we have 4 options
When A = 6 we have 1 option

Alltogether we have 56+35+20+10+4+1 = 126 options
D
Please correct me if i am wrong
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  01 Jan 2018, 05:28

Re:
First Digit - A
Second Digit - B
Third Digit - C
Fourth Digit - D

A can be 1-6
B can be 2-7
C can be 3-8
D can be 4-9
A=1; B = 2; C = 3 ; D = 6 options
A=1; B = 2; C = 4; D = 5 options
A = 1; B=2; C = 5; D = 4 options
A = 1; B=2; C = 6; D = 3 options
A = 1; B=2; C = 7; D = 2 options
A = 1; B=2; C = 8; D = 1 options
So When A =1 and B=2 then we have 21 options
WHen A = 1 and B=3 then we have 15 options
When A =1 and B=4 then we have 10 options
When A = 1 and B=5 then we have 6 options
When A = 1 and B=6 then we have 3 options
When A = 1 and B=7 then we have 1 option
So When A =1 we have 56 options
WHen A = 2 we have 35 options
When A = 3 we have 20 options
When A = 4 we have 10 options
When A = 5 we have 4 options
When A = 6 we have 1 option

Alltogether we have 56+35+20+10+4+1 = 126 options
D
Please correct me if i am wrong
-----------------------------------------------------

in this solution the A is not being considered for '0'...

a clear and simple step would be 10c4.

Please clarify why 0 is left from the numbers.

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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  01 Jan 2018, 06:07

coolnaren wrote:

Re:
First Digit - A
Second Digit - B
Third Digit - C
Fourth Digit - D

A can be 1-6
B can be 2-7
C can be 3-8
D can be 4-9
A=1; B = 2; C = 3 ; D = 6 options
A=1; B = 2; C = 4; D = 5 options
A = 1; B=2; C = 5; D = 4 options
A = 1; B=2; C = 6; D = 3 options
A = 1; B=2; C = 7; D = 2 options
A = 1; B=2; C = 8; D = 1 options
So When A =1 and B=2 then we have 21 options
WHen A = 1 and B=3 then we have 15 options
When A =1 and B=4 then we have 10 options
When A = 1 and B=5 then we have 6 options
When A = 1 and B=6 then we have 3 options
When A = 1 and B=7 then we have 1 option
So When A =1 we have 56 options
WHen A = 2 we have 35 options
When A = 3 we have 20 options
When A = 4 we have 10 options
When A = 5 we have 4 options
When A = 6 we have 1 option

Alltogether we have 56+35+20+10+4+1 = 126 options
D
Please correct me if i am wrong
-----------------------------------------------------

in this solution the A is not being considered for '0'...

a clear and simple step would be 10c4.

Please clarify why 0 is left from the numbers.

Hey coolnaren ...
Can you give me an example of 4-digit no. in which digits are arranged in ascending order and has a "0"
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Posts: 87568

Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  24 Dec 2018, 04:01

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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Posts: 4830

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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  08 Oct 2019, 01:29

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

If we select 4 numbers out of 10 and deselect numbers with 0 as thousandth digit.
10C4 - 9C3 = 126

IMO D
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  11 Oct 2019, 05:38

Kinshook wrote:

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

If we select 4 numbers out of 10 and deselect numbers with 0 as thousandth digit.
10C4 - 9C3 = 126

IMO D

Why do we take combinations? I mean the order is important right(ascending) so shouldn't it be permutation?

Math Expert

Joined: 02 Sep 2009

Posts: 87568

Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  02 Dec 2019, 23:25

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Official Solution:

First of all, notice that 0 cannot be a digit of such numbers: 0 cannot be the first digit, since in this case a number will no longer be a four-digit number and become a three-digit number; and also it cannot be any other digit, since the digits must be in ascending order.

So, such numbers can have only 4 different digits out of 9 (all digits but 0). The number of groups of 4 different digits out of 9 is \(9C4=126\) and since only one arrangement of any of such groups will be in ascending order then 126 is the final answer. For example, if the group of 4 we choose is {3, 5, 7, 1}, the only way to arrange this group of digits in ascending order is 1357.

Answer: D
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  26 Feb 2021, 09:59

I thought of doing this question using permutation so started with filling the 1000th position and we have 9(0 can not be used at 1000th position)options for that. While doing this I realized that answer options do not have big numbers so I can easily divide by 9 and check if I find a unique answer. I divided all options by 9 and only option D passed the test. It was a shortcut to do this question.

Posted from my mobile device

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Joined: 16 Jun 2021

Posts: 1072

Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  31 Aug 2021, 10:16

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

Total ways of chosing 4 digits = 10C4 = 210
total ways of selecting with zero inthousand place =9C3 =84

=>210-83 = 126

Therefore IMO D

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Joined: 01 Apr 2021

Posts: 60

Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
  19 Sep 2021, 01:30

Kinshook wrote:

Bunuel wrote:

GMAT CLUB'S CHALLENGE QUESTIONS:

How many positive four-digit integers have their digits in ascending order from thousands to units?

A. 6
B. 7
C. 84
D. 126
E. 210

If we select 4 numbers out of 10 and deselect numbers with 0 as thousandth digit.
10C4 - 9C3 = 126

IMO D

I don't understand this method..isn't 8765( which is in descending order) included in 10C4?

How many 5 digit numbers are there whose digits are in increasing order?

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Re: How many positive four-digit integers have their digits in ascending [#permalink]

How many 5 digit numbers are there whose digits are in increasing order?
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Re: How many positive four-digit integers have their digits in ascending [#permalink]

18 Nov 2022, 08:21

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How many 5 digit decreasing numbers are there?

We would now get (105)=252 decreasing five digit number.

How many 5 digit numbers are there in the number system?

Q7)How many 5-digit numbers are there in all? So, 90,000 numbers are there in all.

How many five digit numbers can be formed that are the same when the order of their digits is reversed?

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