What is the least number which when divided by 3 5 6 8 10 and 12 leaves in each case a remainder 2 but when divided by 13 leaves no remainder?

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  • What is the least number which when divided by the number 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 22 leaves no remainder ?
  • Solution(By Examveda Team)
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  • What is the least number which on being divided by 5 6 8 9 12 leaves in each case a remainder 1 but when divided by 13 leaves no remainder?
  • What is the least number which on being divided by 5 10 12 and 15 leaves 2 as remainder in each case but if divided by 7 leaves no remainder?
  • When 5 8 and 12 divide a multiple of 13 the remainders left are 3 6 and 10 respectively find the least such number?
  • What is the least number when divided by 5 6 7 and 8 leaves a remainder 3?

  1. A

    312

  2. B

    962

  3. C

    1562

  4. D

    1586

Solution:

By option verification ,

962 is divided by 3,5,6,8,10 and 12 leaves remainder 2, but when divided by 13 leaves no remainder

                     (or)

L.C.M of 3,5,6,8,10,12 is 120

1×120+2=122 is not divisible by 13

2×120+2=242 is not divisible by 13

3×120+2=362 is not divisible by 13

4×120+2=482 is not divisible by 13

5×120+2=602 is not divisible by 13

6×120+2=722 is not divisible by 13

7×120+2=842 is not divisible by 13

8×120+2=962  is divisible by 13

What is the least number which when divided by 3 5 6 8 10 and 12 leaves in each case a remainder 2 but when divided by 13 leaves no remainder?

What is the least number which when divided by the number 3, 5, 6, 8, 10 and 12 leaves in each case a remainder 2 but when divided by 22 leaves no remainder ?

A. 312

B. 242

C. 1562

D. 1586

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{LCM of }}\left( {3,5,6,8,10,12} \right) \cr & = 3 \times 5 \times 2 \times 4 \cr & = 120 \cr & {\text{Required number is }} \cr & \frac{{120K + 2}}{{22}} = \frac{{10K + 2}}{{22}} \cr & {\text{at }}K{\text{ = 2,}}\frac{{10K + 2}}{{22}} \cr & \Rightarrow {\text{Remainder = 0}} \cr & {\text{The given condition satisfied}} \cr & {\text{ = }}120K + 2 \cr & = 240 + 2 \cr & = 242 \cr} $$


Given:

The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3

The least number when divided by 9 remainder = 0

Concept Used:

For the least number take LCM and also check that all conditions are satisfying or not

For same remainder in each case add the remainder in the LCM 

Calculation:

First we have to find the LCM of 5, 6, 7, 8

5 = 51

6 = 21 × 31 

7 = 71 

8 = 23 

LCM of 5, 6, 7, 8 is 23 × 31 × 51 × 71 = 840

For same remainder we have to add 3 to the LCM

⇒ 840 + 3 

Now check weather it is divisible by 9 or not

843/9 = Not divisible by 9

Now we have to take next multiple of LCM and then add 3

840 × 2 + 3

⇒ 1683

Divide it by 9

1683/9 = 187

⇒ 1683 is divisible by 9 

⇒ 1683 is the least number when divided by 5, 6, 7, 8 gives remainder 3

Shortcut Trick

The least number must be divisible by 9 

For divisibility of 9 sum of digits of the number must be divisible by 9 

Checking it by options:

Option 1) 1677

1 + 6 + 7 + 7 = 21

⇒ 1677 is not divisible by 9

Option 2) 1683

1 + 6 + 8 + 3 = 18

⇒ 1683 is divisible by 9

Option 3) 2523

2 + 5 + 2 + 3 = 12

⇒ 2523 is not divisible by 9

Option 4) 3363

3 + 3 + 6 + 3 = 15

⇒ 3363 is not divisible by 9

∴ The least number is 1683 which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

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Updated On: 27-06-2022

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Text Solution

31224215621586

Answer : B

Answer

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What is the least number which on being divided by 5 6 8 9 12 leaves in each case a remainder 1 but when divided by 13 leaves no remainder?

∴ The least number which is divided by 5, 6, 8, 9, 12 leaves a remainder 1 but when divided by 13 leaves no remainder is 3601. Option A is the correct option.

What is the least number which on being divided by 5 10 12 and 15 leaves 2 as remainder in each case but if divided by 7 leaves no remainder?

∴ The number is 64.

When 5 8 and 12 divide a multiple of 13 the remainders left are 3 6 and 10 respectively find the least such number?

Only one answer remains, 598.

What is the least number when divided by 5 6 7 and 8 leaves a remainder 3?

∴ The least number is 1683 which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

What is the least number which when divided by 5 6 8 10 and 12?

∴ The least number which is exactly divisible by 5, 6, 8, 10, and 12 is 120.

What is the least number which when divided by either 3 5 7 11 and 13 leaves a reminder of 1 in each case?

This is Expert Verified Answer The least number that leaves a "remainder 3" when divided by "5, 7 and 13" is 458.

What is the lowest number which leaves 3 as reminder when divided by 8 12 and 16?

The correct option is A 51.

When 5 8 and 12 divide a multiple of 13 the remainders left are 3 6 and 10 respectively find the least such number?

Only one answer remains, 598.