How do you get the first and last digit of a number in python?

View Discussion

Improve Article

Save Article

View Discussion

Improve Article

Save Article

Given a number and to find first and last digit of a number.
Examples: 
 

Input : 12345 
Output : First digit: 1
         last digit : 5

Input : 98562
Output : First digit: 9
         last digit : 2

To find last digit of a number, we use modulo operator %. When modulo divided by 10 returns its last digit. 
Suppose if n = 1234 
then last Digit = n % 10 => 4 
To finding first digit of a number is little expensive than last digit. To find first digit of a number we divide the given number by 10 until number is greater than 10. At the end we are left with the first digit.
 

Approach 1 (With loop):

C++

#include

using namespace std;

int firstDigit(int n)

{

    while (n >= 10) 

        n /= 10;

    return n;

}

int lastDigit(int n)

{

    return (n % 10);

}

int main()

{

    int n = 98562;

    cout << firstDigit(n) << " " 

        << lastDigit(n) << endl;

    return 0;

}

Java

import java.util.*;

import java.lang.*;

public class GfG{

    public static int firstDigit(int n)

    {

        while (n >= 10) 

            n /= 10;

        return n;

    }

    public static int lastDigit(int n)

    {

        return (n % 10);

    }

    public static void main(String argc[])

    {

        int n = 98562;

        System.out.println(firstDigit(n) + " "

        + lastDigit(n));

    }

}

Python3

def firstDigit(n) :

    while n >= 10: 

        n = n / 10;

    return int(n)

def lastDigit(n) :

    return (n % 10)

n = 98562;

print(firstDigit(n), end = " ") 

print(lastDigit(n))

C#

using System;

public class GfG{

    public static int firstDigit(int n)

    {

        while (n >= 10) 

            n /= 10;

        return n;

    }

    public static int lastDigit(int n)

    {

        return (n % 10);

    }

    public static void Main()

    {

        int n = 98562;

        Console.WriteLine(firstDigit(n) + " "

        + lastDigit(n));

    }

}

PHP

function firstDigit($n)

{

    while ($n >= 10)